Difficulty: Hard
Correct Answer: 22 2/9%
Explanation:
Introduction / Context:
This is a classic “faulty balance” puzzle from profit-and-loss, where the two pans are not equivalent. The right pan effectively adds 200 g of extra pull compared to the left. The merchant cleverly places goods and weights in different pans while buying and selling, creating a hidden gain despite “selling at cost price”. The goal is to compute the true profit percentage caused purely by mismeasurement and pan asymmetry.
Given Data / Assumptions:
Concept / Approach:
Work with one 2 kg operation and then generalize (linearity). Because the right pan is 200 g heavier, the side carrying the right pan requires a smaller true mass to balance when it holds goods, and a larger true mass when it holds the counterweight. Convert each 2 kg nominal transaction into true kilograms to find effective buying cost per true kg and effective selling price per true kg. Profit% = (SP_true − CP_true) / CP_true * 100.
Step-by-Step Solution:
Verification / Alternative check:
Consider n repeats; both received and delivered masses scale proportionally, so the ratio (and hence percentage) remains 22 2/9%. The arithmetic above uses only one 2 kg cycle for clarity.
Why Other Options Are Wrong:
20% and 18 2/11% ignore one of the two biases (buy and sell). “None of these” and 25% do not match the exact ratio 11/9 obtained from simultaneous buying and selling effects.
Common Pitfalls:
Forgetting that the heavier right pan helps the merchant in opposite ways when it holds the goods versus the weight. Another mistake is computing on declared kilograms instead of converting to true kilograms first.
Final Answer:
22 2/9%
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