Father–Son — “A father says: ‘I was three times your present age when you were born.’ The father is now 48. How old was the boy 4 years ago?”

Difficulty: Medium

Correct Answer: 8 years

Explanation:

Introduction / Context:The sentence compares the father’s age at the son’s birth (a past time) with the son’s present age. Translate it carefully into a linear equation, then answer the question about the boy 4 years ago.

Given Data / Assumptions:

  • Father’s present age = 48.
  • Let son’s present age = x.
  • At son’s birth (x years ago), father’s age = 48 − x.
  • Statement: 48 − x = 3x.

Concept / Approach:Age differences are constant, but here we directly set father’s past age equal to a multiple of the son’s present age. Solve for x and then subtract 4 for “4 years ago.”

Step-by-Step Solution:

48 − x = 3x ⇒ 48 = 4x ⇒ x = 12 (boy now).Boy 4 years ago = 12 − 4 = 8 years.

Verification / Alternative check:At birth: father 48 − 12 = 36, which is indeed 3 × 12 (the son’s current age). Consistent.

Why Other Options Are Wrong:10/12/16/24 do not represent “boy’s present age 12, four years earlier” which must be 8.

Common Pitfalls:Setting 48 = 3x (missing the “at birth” shift), or subtracting 4 from father’s age rather than the boy’s age.

Final Answer:8 years

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