Liquid–liquid extraction — For a useful separation, the distribution selectivity should be...
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A> 1 (greater than one)
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B< 1 (less than one)
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CEqual to 1
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DZero
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ENegative
Answer
Correct Answer: > 1 (greater than one)
Explanation
Introduction:In extraction, selectivity quantifies preferential partitioning of a solute between phases, typically defined as a ratio of distribution coefficients or partition coefficients for desired vs undesired species. A favorable selectivity is critical for stage efficiency and solvent economy.
Given Data / Assumptions:
- Standard definition of selectivity S as a ratio exceeding unity for favorable separation.
- Isothermal operation without chemical reaction.
- Steady partitioning behavior.
Concept / Approach:When S > 1, the target component prefers the extract phase relative to the raffinate or relative to impurities, enabling effective separation with a reasonable number of stages. S ≤ 1 implies poor or no selectivity, demanding impractical solvent flows or excessive stages.
Step-by-Step Solution:Recall definition: S = K_A / K_B for components A and B or equivalent selectivity expression.Assess requirement: For enrichment, S must exceed unity.Conclude that S > 1 is desired.
Verification / Alternative check:McCabe–Thiele style constructions for extraction show rapidly converging stage counts when S > 1 and divergence when S ≤ 1.
Why Other Options Are Wrong:
- < 1 or = 1 provide little to no driving force.
- Zero or negative are nonphysical in this context.
Common Pitfalls:Confusing distribution ratio D with selectivity S; assuming constant S when complexation or pH effects change partitioning.
Final Answer:> 1 (greater than one)