Difficulty: Easy
Correct Answer: Repeater
Explanation:
Introduction / Context:10BASE2 (thin Ethernet, RG-58 coax) has a strict maximum segment length of 185 m between terminators. Exceeding this without regeneration leads to attenuation and collision-domain issues. When you need more distance on the same physical medium and wish to remain within the same collision domain, a physical-layer device is the correct tool.
Given Data / Assumptions:
Concept / Approach:A repeater (or an active hub for the appropriate medium) regenerates and reshapes the signal, effectively starting a new compliant segment while preserving one collision domain. T-connectors are only passive taps in 10BASE2 chains. Routers and gateways segment at higher layers and are unnecessary if you only need to extend the same segment physically. A bridge would create a new collision domain and requires appropriate media interfaces; the simplest, standards-aligned solution for same-medium extension is a repeater placed between segments, observing Ethernet’s repeater and segment-count rules.
Step-by-Step Solution:
Recognize the 185 m limit for a single 10BASE2 segment. To add distance on the same medium, use a Layer-1 device that regenerates bits → repeater. Ensure proper terminators and T-connectors at segment ends and host taps. Conclude: Add a repeater between the two coax segments.Verification / Alternative check:10BASE2 design guidelines allow multiple segments interconnected by repeaters, within the classic Ethernet repeater rules. This maintains timing for CSMA/CD and keeps collisions detectable across the extended shared medium.
Why Other Options Are Wrong:
Common Pitfalls:Confusing passive tap hardware with active signal regeneration; forgetting terminators (50-ohm) at both ends of each coax segment; overlooking repeater count and topology rules in classic Ethernet.
Final Answer:Repeater
Discussion & Comments