Curioustab
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Aptitude
General Knowledge
Verbal Reasoning
Computer Science
Interview
Home
»
Electronics
»
Series-Parallel Circuits
In a series–parallel circuit, individual component power dissipations are calculated using:
individual component parameters
a percent of the voltage division ratio squared
total current squared multiplied by the resistor values
a percent of the total power depending on resistor ratios
Correct Answer:
individual component parameters
← Previous Question
Next Question→
More Questions from
Series-Parallel Circuits
What is the total resistance of the given circuit?
What is the power dissipated by R1, R2, and R3?
In the given circuit, what is RUNK equal to if RV must be adjusted to 1,232 Ω in order to balance the bridge?
A Wheatstone bridge can be used to determine an unknown
If the load in the given circuit is 12 kΩ , what is the loaded output voltage?
If R1 is in series with parallel connected to R2 and R3, what happens to total current if R2 opens?
The first goal(s) to accomplish in analyzing a complex series–parallel circuit is to:
What is the voltage to the load?
If the load in the given circuit is open, what is the unloaded output voltage?
If a series–parallel circuit has all 30-ohm resistors, what is the total resistance when R1 is in series with a parallel circuit consisting of R2 and R3?
Discussion & Comments
No comments yet. Be the first to comment!
Name:
Comment:
Post Comment
Join Discussion
Discussion & Comments