Difficulty: Easy
Correct Answer: DeMorgan's second theorem
Explanation:
Introduction / Context:
Bubble notation captures logical inversion on gate inputs and outputs. DeMorgan’s theorems formalize how inversions move across AND/OR gates while swapping the gate type, a powerful technique for designing with NAND/NOR-only libraries and for reading schematics quickly.
Given Data / Assumptions:
Concept / Approach:
DeMorgan’s second theorem states (A + B)' = A' • B'. Interpreted in gate form, an OR with both inputs inverted (bubbled-input OR) yields the same function as an AND with an inverted output (bubbled-output AND), i.e., NOR ≡ AND-with-inverted-inputs and equally NAND ≡ OR-with-inverted-inputs depending on the specific form used.
Step-by-Step Solution:
Start with Y = (A + B)'.Apply DeMorgan: Y = A' • B'.Map to gates: left side is an OR with output bubble (NOR) or equivalently an OR with bubbled inputs feeding an AND.Thus, a bubbled-input OR and a bubbled-output AND implement the same logic.
Verification / Alternative check:
Truth tables or logic-simulation confirm functional identity. Schematic re-drawing with bubble-pushing gives identical simplified forms.
Why Other Options Are Wrong:
Karnaugh map: a minimization tool, not a law.Commutative / associative laws: reorder or regroup operations; they do not involve inversion movement.
Common Pitfalls:
Confusing input versus output bubbles. DeMorgan requires flipping the gate type while inverting all lines that cross the inversion boundary.
Final Answer:
DeMorgan's second theorem
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