Difficulty: Easy
Correct Answer: decreases as gate current is increased
Explanation:
Introduction / Context:
The forward breakover voltage of a thyristor is the anode-to-cathode voltage at which the device turns on without a gate signal. In practical use, a gate current is applied to trigger conduction at a lower voltage. Understanding this relationship is essential for reliable gating circuits.
Given Data / Assumptions:
Concept / Approach:
Increasing gate current reduces the required anode-cathode voltage to reach conduction by preconditioning the device’s internal junctions (regenerative feedback starts earlier). Therefore, the effective forward breakover voltage is lowered as gate current increases.
Step-by-Step Solution:
At zero gate current, forward breakover is at the datasheet-specified highest value.Apply a small gate current: conduction begins at a lower anode-cathode voltage.As gate current rises further (within allowable limits), the turn-on voltage continues to decrease.
Verification / Alternative check:
SCR V–I curves with different Ig values show a leftward shift of the triggering point as Ig increases, confirming the decrease in forward breakover voltage.
Why Other Options Are Wrong:
Constant or increases: Contradicts the fundamental regenerative turn-on aided by gate drive.
“May be constant or may depend”: Too vague; in practice it does depend and decreases with higher gate current.
Common Pitfalls:
Confusing holding or latching current with breakover voltage; those are separate parameters.
Final Answer:
decreases as gate current is increased
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