Single-phase step-up cycloconverter: 50 Hz to 100 Hz A single-phase step-up cycloconverter converts 50 Hz input to 100 Hz output. One half-wave of the 50 Hz input will produce how many output waves?

Introduction / Context:
Cycloconverters synthesize a new frequency directly from an AC input without a DC link by segmenting and recombining portions of the input waveform through phase-controlled devices. A step-up cycloconverter produces an output frequency higher than the input by proper gating and polarity reversal within smaller time windows.

Given Data / Assumptions:

• Input frequency = 50 Hz, period T.
• Output frequency = 100 Hz, period T/2.
• Ideal switching and sufficient device count are assumed.

Concept / Approach:

For a frequency-doubling (50 → 100 Hz), the converter must produce a complete output cycle in half the input period. Thus, within one input half-cycle (duration T/2), the control scheme constructs both the positive and negative half-waves of the output in sequence to total one full 100 Hz cycle.

Step-by-Step Solution:

Verification / Alternative check:

Frequency-doubling control waveforms for step-up cycloconverters in textbooks show exactly one output cycle generated during each input half-cycle.

Why Other Options Are Wrong:

Half wave (a) is insufficient; two full waves (c) would imply 200 Hz; (d) is incorrect for a fixed 2:1 step-up; (e) contradicts operation.

Common Pitfalls:

Assuming cycloconverters only step down; overlooking polarity inversion and gating schemes required to synthesize the higher frequency.

Final Answer:

One full wave of output