n-stage high-frequency series inverter (total time period T) For an inverter composed of n identical series-resonant stages operating in sequence within one period T, how long is each stage active?

Difficulty: Easy

Correct Answer: T/n

Explanation:


Introduction / Context:
Multi-stage high-frequency series inverters distribute the switching and resonant intervals among several identical stages to increase effective output frequency and reduce component stress. Understanding timing allocation per stage is key for design and control.


Given Data / Assumptions:

  • Total inverter period is T.
  • There are n identical resonant stages.
  • Stages operate sequentially and non-overlapping within T.


Concept / Approach:

If the stages share the cycle equally and operate one after another without overlap, the simplest time division gives each stage an equal slice of T. Hence, each stage remains active for T/n while the others are idle or preparing for the next interval. This evenly apportions resonant energy exchange and switch stress among stages.


Step-by-Step Solution:

Assume uniform time-division multiplexing of resonant actions.Total period T = sum of n equal active intervals.Therefore each active interval per stage = T / n.


Verification / Alternative check:

Design examples and timing diagrams demonstrate equal-length gating windows to maintain symmetry and balance among identical stages.


Why Other Options Are Wrong:

T/2n implies overlaps or double counting; T means only one stage would operate; T/(n − 1) has no basis in equal partitioning for n stages.


Common Pitfalls:

Assuming unequal sharing without a specified reason; overlooking dead-time which, if present, is typically small and still leads to approximately T/n per stage.


Final Answer:

T/n

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