Difficulty: Easy
Correct Answer: Over-voltage
Explanation:
Introduction / Context:
Current chopping occurs when a current in an inductive path is interrupted rapidly before naturally decaying to zero. This is common in circuit breakers and some controlled converters, and understanding the resulting transient is crucial to insulation coordination and snubber design.
Given Data / Assumptions:
Concept / Approach:
Inductors oppose sudden change in current. For a rapid current drop, the inductor generates a voltage v_L = L * di/dt in whatever polarity is needed to keep current flowing. A large negative di/dt therefore produces a high magnitude voltage spike, risking insulation breakdown unless snubbers, varistors, or free-wheeling paths are provided.
Step-by-Step Solution:
Assume current I is chopped to a smaller value (even to zero) in a short time Δt.Then di/dt ≈ −I/Δt → large magnitude.Induced voltage v_L = L * di/dt → large over-voltage unless clamped.
Verification / Alternative check:
Oscillograms of chopped currents show voltage spikes coincident with interruption. Proper snubbers limit dv/dt and peak v.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Over-voltage
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