Assertion–Reason in DC choppers: Assertion (A): If the duty cycle of a chopper is low, the current would not become discontinuous. Reason (R): If the load time constant L/R is low, the current may become discontinuous.

Difficulty: Medium

Correct Answer: A is wrong but R is correct

Explanation:


Introduction / Context:
Chopper-fed inductive loads can operate in continuous or discontinuous current mode depending on switching parameters and the load time constant. This assertion–reason item probes how duty cycle and L/R affect current continuity.


Given Data / Assumptions:

  • Chopper with R–L load.
  • Duty cycle D can be low or high.
  • Load time constant τ = L / R sets current decay rate during OFF time.


Concept / Approach:
Low duty cycle implies longer OFF time fraction, giving current more time to decay. A small τ (low L/R) also causes faster decay. Both conditions favor discontinuous current. Hence, the assertion that low duty cycle prevents discontinuity is wrong; the reason that small L/R can cause discontinuity is correct.


Step-by-Step Solution:

During OFF time, i(t) decays approximately as i * exp(−t/τ).Lower duty cycle → larger OFF interval → more decay → more likely i reaches zero → discontinuous mode.Smaller τ = L/R → faster exponential decay → increased chance of discontinuity.Therefore: Assertion (A) is wrong; Reason (R) is correct.


Verification / Alternative check:

Simulation or timing diagrams confirm that elongated OFF periods and small τ values produce discontinuous current at moderate loads.


Why Other Options Are Wrong:

Any option claiming A is correct contradicts chopper current decay physics.Saying R is wrong ignores the well-known impact of τ on decay.


Common Pitfalls:

Assuming duty cycle only changes average voltage, not current mode; overlooking the exponential nature of inductor current decay.


Final Answer:

A is wrong but R is correct

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