Sizing parallel thyristors with derating A 750 A DC circuit uses identical thyristors each rated at 175 A. With a derating factor of 25% (i.e., each device carries only 75% of its nameplate current), how many thyristors must be placed in parallel?

Difficulty: Easy

Correct Answer: 6

Explanation:


Introduction / Context:
When paralleling thyristors, current sharing is imperfect due to tolerances and temperature coefficients. A derating factor is applied so each device is loaded below its nominal rating, ensuring reliability. Calculating the required count is a straightforward but essential design step.


Given Data / Assumptions:

  • Total circuit current Itotal = 750 A.
  • Device nameplate Irated = 175 A.
  • Derating 25% → usable per device Iusable = 0.75 * Irated.


Concept / Approach:

Number of devices in parallel n must satisfy n * Iusable ≥ Itotal. Use ceiling to ensure sufficient devices.


Step-by-Step Solution:

Iusable = 0.75 * 175 = 131.25 A.n ≥ 750 / 131.25 ≈ 5.714...Minimum integer n = 6.


Verification / Alternative check:

Check margin: 6 * 131.25 = 787.5 A ≥ 750 A → acceptable.


Why Other Options Are Wrong:

3, 4, or 5 do not meet the required current with derating; 10 is over-conservative for the stated parameters.


Common Pitfalls:

Forgetting to apply derating; using rounding down instead of ceiling.


Final Answer:

6

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