Rectangular resonant cavity — mode existence rules Which of the following modes cannot exist in a rectangular resonant cavity?

Difficulty: Easy

Correct Answer: TM110

Explanation:


Introduction / Context:
Electromagnetic modes in a rectangular cavity are classified as TEmnp or TMmnp, where m, n, p count half-wave variations along the a, b, and d dimensions. Existence rules differ for TE and TM families because of boundary conditions on tangential fields at conducting walls.


Given Data / Assumptions:

  • Perfectly conducting rectangular cavity with dimensions a, b, d.
  • Mode indices m, n, p are nonnegative integers.


Concept / Approach:
For TM modes in a cavity, the axial electric field component must be nonzero and satisfy boundary conditions on all six walls. This enforces that all three indices m, n, and p must be nonzero (≥ 1). If any of m, n, or p is zero, the required field configuration cannot satisfy the boundary conditions for TM in a closed cavity. In contrast, TE modes may have one index equal to zero, provided not all are zero simultaneously.


Step-by-Step Solution:

Check TM110: p = 0 → violates TM requirement that m, n, p ≥ 1 → cannot exist.Check TE110: allowed; TE permits a zero or more in indices as long as fields satisfy boundary conditions.Check TE011: allowed for the same reason (TE with m = 0 is permissible).Check TM111: allowed; all indices nonzero.


Verification / Alternative check:
Standard cavity-mode tables list TMmnp only with m, n, p ≥ 1, while TEmnp may include zeros. This corroborates the exclusion of TM110.


Why Other Options Are Wrong:

  • TE110 and TE011: valid TE modes with appropriate boundary conditions.
  • TM111: all indices nonzero → valid TM mode.


Common Pitfalls:
Assuming waveguide rules carry over directly; in a closed cavity, TM requires three standing-wave variations.


Final Answer:
TM110

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