Mode identification in a rectangular waveguide: If the electric field shows one half-wave variation across the narrow wall and two half-wave variations across the broad wall, what is the resulting dominant mode notation?

Difficulty: Easy

Correct Answer: TE21

Explanation:


Introduction / Context:
Rectangular waveguides label modes as TEmn or TMmn. The first index m counts half-wave variations across the broad dimension a, and the second index n counts half-wave variations across the narrow dimension b. Accurately mapping spatial variations to indices is a common exam task.



Given Data / Assumptions:

  • Across the narrow side (b): one half-wave variation.
  • Across the broad side (a): two half-wave variations.
  • We are to provide the correct mode label.


Concept / Approach:

By convention, m corresponds to the broad dimension a and n to the narrow dimension b. Two variations across a imply m = 2; one across b implies n = 1. Because the statement refers to the electric-field pattern in a typical hollow guide, the appropriate family is TE. Therefore, the mode is TE21.



Step-by-Step Solution:

Assign indices from variations: m = 2 (broad), n = 1 (narrow).Select family: TE, as commonly discussed for such field distributions.Write the final mode: TE21.Confirm it matches the described field pattern.


Verification / Alternative check:

Field sketches for TE21 exhibit two lobes along a and one along b, consistent with the description. Reference charts align with this notation.



Why Other Options Are Wrong:

  • TM12 and TM25: wrong indices and family.
  • TE13: implies three variations across b, not one.
  • TE02: implies zero variations along a, which contradicts the given two.


Common Pitfalls:

Swapping a and b or forgetting which index maps to which dimension.



Final Answer:

TE21

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