A TV allocation has a total available spectrum of approximately 300 MHz. Assuming standard 6 MHz channel spacing, the number of TV channels that can be accommodated is approximately:

Difficulty: Easy

Correct Answer: 50

Explanation:


Introduction:
Broadcast allocations divide spectrum into fixed-width channels. Estimating the number of channels from a total bandwidth is a straightforward bandwidth-division calculation used in spectrum planning.


Given Data / Assumptions:

  • Total spectrum ≈ 300 MHz
  • Per-channel bandwidth ≈ 6 MHz
  • Guard bands and practical constraints are neglected for a rough estimate


Concept / Approach:
The approximate number of channels equals total bandwidth divided by per-channel bandwidth. For rough planning and exam problems, guard bands are often ignored unless specified.


Step-by-Step Solution:

1) Use count = Total_BW / Channel_BW.2) Substitute: 300 MHz / 6 MHz = 50.3) Therefore, about 50 TV channels can be accommodated.


Verification / Alternative check:
If small guard bands are included, the practical number may be slightly lower, but 50 remains the standard back-of-the-envelope figure for 300 MHz at 6 MHz spacing.


Why Other Options Are Wrong:

  • A/B: 5 or 10 would imply much larger channel bandwidths or very little spectrum.
  • D: 200 would require channels of ~1.5 MHz, not typical for analog/ATSC-like allocations.


Common Pitfalls:
Mixing regional standards (e.g., 7/8 MHz in some countries) without being told; forgetting to keep units consistent.


Final Answer:
50

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