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If D is diameter of circular waveguide the cutoff wave-length for TE11 mode is equal to

Correct Answer: 1.706 D

Explanation:

Some applications require dual polarization capability. Circular waveguide has this capability.


These analysis uses cylindrical coordinates.


In circular waveguide TE11 mode has the lowest cut off frequency and is the dominant mode.


If D is diameter of waveguide


λc = 1.706 D for TE11 mode


λc = 1.029 D for TE21 mode


λc = 0.82 D for TE01 mode


λc = 1.306 D for TM01 mode.


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