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Exam Questions Papers
The inverse of given Laplace transform is
sin t
cos t
et
e2t
Correct Answer:
cos t
Explanation:
s
=
x
2
-
e
x
x
(
t
) = cos
t
.
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Consider the common emitter amplifier shown below with the following circuit parameters: β = 100, gm = 0.3861 A/V, r0 = ∞ rp = 259 Ω, Rs = 1 kΩ, RB = 93 kΩ, RC = 250 Ω, RL = 1 kW, C1 = ∞ and C2 = 4.7mF. The resistance seen by the source Vs is
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