c(t) and m(t) are used to generate an FM signal. If the peak frequency deviation of the generated FM signal is three times the transmission bandwidth of the AM signal, then the coefficient of the term cos [2p(1008 x 103t)] in the FM signal (in terms…

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As, we known FM, s(t)

⟹ Frequency deviation = 3 . (AM Bandwidth) = 6 f_m

and β= 6 is given in (d) only.

ω_c + n ω_m = (1008 x 10³)2p

⟹ 2p x 10⁶ + n. 4p x 10³ = (1008 x 10³).2p

⟹ n = 4

So, β = 6, n = 4 hence answer is 5j₄(6).

c(t) and m(t) are used to generate an FM signal. If the peak frequency deviation of the generated FM signal is three times the transmission bandwidth of the AM signal, then the coefficient of the term cos [2p(1008 x 103t)] in the FM signal (in terms of the Bessel Coefficients) is

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