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A 47 Ω resistor and a capacitor with 150 Ω of capacitive reactance are in series across an ac source. The impedance, expressed in rectangular form, is

Z = 47 Ω + j150 Ω
Z = 47 Ω – j150 Ω
Z = 197 Ω
Z = 103 Ω

Correct Answer: Z = 47 Ω – j150 Ω

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