A 2 kΩ resistor is in series with a 0.015 µF capacitor across a 15 kHz ac source. What is the magnitude of the total impedance and the phase angle?

Correct Answer: 2121 Ω and θ = –19.5°

Explanation:

Xc = 1/2πfC = 707 Ω

Z = R - jXc = 2000 - j(707)

|z| = sqrt(R*R + Xc*Xc) = 2121 Ω

Phase angle = arctangent(Xc/R) = 19.5°

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