Edeleanu solvent extraction of kerosene In the Edeleanu process (liquid SO2 extraction at about −20 °C), which component family in kerosene is preferentially reduced to improve burning quality?

Difficulty: Easy

Correct Answer: Aromatics

Explanation:


Introduction / Context:
The Edeleanu process uses liquid sulphur dioxide as a selective solvent to improve kerosene quality. Lower aromatic content generally improves smoke point and combustor performance by reducing soot formation.


Given Data / Assumptions:

  • Operating temperature is near −20 °C.
  • Feed: kerosene-range hydrocarbons.
  • Goal: enhance burning characteristics (smokeless flame).


Concept / Approach:
Liquid SO2 preferentially dissolves aromatics. Extraction transfers aromatics into the solvent-rich phase, leaving a raffinate leaner in aromatics. Since aromatics correlate with lower smoke point, their reduction raises the smoke point and improves flame luminosity behavior.


Step-by-Step Solution:

Note that smoke/soot tendency tracks with aromatic content.Recognize that Edeleanu extraction removes aromatics selectively.Therefore, the process reduces the aromatics in kerosene.


Verification / Alternative check:
Classic refining texts list Edeleanu under aromatic extraction processes for kerosene/jet precursors.


Why Other Options Are Wrong:

  • Paraffins / Naphthenes: These are not the primary targets; they remain largely in the raffinate.
  • Smoke point: Smoke point is a property, not a component family; the process raises smoke point by reducing aromatics.


Common Pitfalls:
Interpreting the property “smoke point” itself as the thing being extracted; in reality, component removal changes the property.


Final Answer:
Aromatics

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