Edeleanu solvent extraction of kerosene In the Edeleanu process (liquid SO2 extraction at about −20 °C), which component family in kerosene is preferentially reduced to improve burning quality?
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AAromatics
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BParaffins
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CNaphthenes
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DSmoke point
Answer
Correct Answer: Aromatics
Explanation
Introduction / Context:The Edeleanu process uses liquid sulphur dioxide as a selective solvent to improve kerosene quality. Lower aromatic content generally improves smoke point and combustor performance by reducing soot formation.
Given Data / Assumptions:
- Operating temperature is near −20 °C.
- Feed: kerosene-range hydrocarbons.
- Goal: enhance burning characteristics (smokeless flame).
Concept / Approach:Liquid SO2 preferentially dissolves aromatics. Extraction transfers aromatics into the solvent-rich phase, leaving a raffinate leaner in aromatics. Since aromatics correlate with lower smoke point, their reduction raises the smoke point and improves flame luminosity behavior.
Step-by-Step Solution:
Note that smoke/soot tendency tracks with aromatic content.Recognize that Edeleanu extraction removes aromatics selectively.Therefore, the process reduces the aromatics in kerosene.Verification / Alternative check:Classic refining texts list Edeleanu under aromatic extraction processes for kerosene/jet precursors.
Why Other Options Are Wrong:
- Paraffins / Naphthenes: These are not the primary targets; they remain largely in the raffinate.
- Smoke point: Smoke point is a property, not a component family; the process raises smoke point by reducing aromatics.
Common Pitfalls:Interpreting the property “smoke point” itself as the thing being extracted; in reality, component removal changes the property.
Final Answer:Aromatics