Difficulty: Easy
Correct Answer: Catalyze the oxidation of pyruvate to acetyl-CoA and CO2
Explanation:
Introduction:The pyruvate dehydrogenase complex (PDC) links glycolysis to the tricarboxylic acid (TCA) cycle by converting pyruvate into acetyl-CoA. This question checks recognition of the oxidative decarboxylation step that produces acetyl-CoA, CO2, and reduced cofactors crucial for aerobic metabolism.
Given Data / Assumptions:
Concept / Approach:PDC performs oxidative decarboxylation. Thiamine pyrophosphate (TPP) decarboxylates pyruvate, lipoamide accepts the acyl group, CoA forms acetyl-CoA, and FAD/NAD+ reoxidize the lipoamide. The net effect is oxidation of pyruvate coupled to the formation of acetyl-CoA and CO2 with generation of NADH.
Step-by-Step Solution:
E1: TPP-dependent decarboxylation of pyruvate → hydroxyethyl-TPP.E2: Transfer of the two-carbon unit to lipoamide, then to CoA → acetyl-CoA.E3: Reoxidation of reduced lipoamide via FAD and NAD+ → NADH + H+.CO2 is released during decarboxylation, establishing the link to TCA entry.Verification / Alternative check:Stoichiometry: pyruvate + CoA + NAD+ → acetyl-CoA + CO2 + NADH + H+, matching oxidative decarboxylation rather than reduction.
Why Other Options Are Wrong:
Common Pitfalls:Confusing PDC with pyruvate carboxylase or lactate dehydrogenase; forgetting NADH production.
Final Answer:Catalyze the oxidation of pyruvate to acetyl-CoA and CO2
Discussion & Comments