Difficulty: Easy
Correct Answer: 1 FADH2, 1 NADH and 1 acetyl-CoA
Explanation:
Introduction / Context:
β-oxidation shortens fatty acyl chains by two carbons per cycle and provides reducing equivalents for ATP production. Knowing the per-cycle output is key for calculating total ATP yield from a given fatty acid.
Given Data / Assumptions:
Concept / Approach:
Each cycle comprises two oxidations and one thiolytic cleavage. The two-carbon unit leaves as acetyl-CoA; the chain is shortened to re-enter the next cycle until fully degraded.
Step-by-Step Solution:
Dehydrogenation: acyl-CoA → trans-enoyl-CoA + FADH2.Hydration: trans-enoyl-CoA + H2O → L-3-hydroxyacyl-CoA.Dehydrogenation: L-3-hydroxyacyl-CoA → 3-ketoacyl-CoA + NADH.Thiolysis: 3-ketoacyl-CoA + CoA → acetyl-CoA + shortened acyl-CoA.
Verification / Alternative check:
Textbook ATP yield calculations for palmitate incorporate per-cycle production of 1 FADH2, 1 NADH, and 1 acetyl-CoA (with a final extra acetyl-CoA on the last cleavage).
Why Other Options Are Wrong:
Options with CO2 are incorrect; CO2 is produced in the citric acid cycle, not β-oxidation.Listing NAD+ or FAD as products is incorrect; they are oxidized cofactors consumed, not produced.Propionyl-CoA arises from odd-chain oxidation, not even-chain substrates.
Common Pitfalls:
Mixing β-oxidation outputs with TCA outputs; forgetting that the final round yields an additional acetyl-CoA without another FADH2/NADH set.
Final Answer:
1 FADH2, 1 NADH and 1 acetyl-CoA.
Discussion & Comments