Difficulty: Easy
Correct Answer: Slightly weaker in proteins than in water
Explanation:
Introduction / Context:
Hydrogen bonding stabilizes secondary structure (α-helices and β-sheets) in proteins. However, in aqueous solution a hydrogen bond broken inside a protein can often be replaced by new hydrogen bonds to water. The small energetic cost reported for bond breakage during helix unfolding helps interpret the balance between intraprotein and water-mediated hydrogen bonding.
Given Data / Assumptions:
Concept / Approach:
In thermodynamics of folding, intramolecular hydrogen bonds compete with hydrogen bonds to water. If breaking a helix hydrogen bond required a large energy, that would imply markedly stronger bonds in proteins. A modest ~2 kJ/mol cost indicates that when one H-bond is disrupted, new H-bonds with water almost compensate, making the net cost small. Thus, protein H-bonds are not drastically stronger; if anything, they are slightly weaker or only marginally favorable relative to solvent H-bonding.
Step-by-Step Solution:
Identify the reported bond breakage energy: ~2 kJ/mol (small).Infer that water quickly re-forms H-bonds with exposed donors/acceptors.Conclude that intraprotein H-bonds are slightly less favorable than water H-bonds.
Verification / Alternative check:
Experimental unfolding energetics and molecular dynamics show that hydrogen bonds contribute modestly to stability in water; hydrophobic packing and side-chain interactions often dominate.
Why Other Options Are Wrong:
Common Pitfalls:
Assuming that any hydrogen bond automatically confers large stability; context (solvent competition) matters.
Final Answer:
Slightly weaker in proteins than in water.
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