The watch which gains uniformly is 2 minutes. slow at noon on Sunday and is 4 minutes. 48 seconds. fast at 2 pm on the following Sunday. The watch was correct at:

We know that, any relative position of the hands of a clock is repeated 11 times in every 12 hours.
? In every 12 hours, hands coincide 11 times and are opposite to each other 11 times.
? In every 12 hours, hands are in a straight line 11 + 11 = 22 times.
? In every 24 hours hands are in a straight line 44 times.

As per the given above question , we can say that
At 11 O'clock, the hour hand is 4 spaces apart from the minute hand. Since there are 60 spaces in one hour, so (60 - 4) times, i.e., 56 times the hands of the clock are an integral number of minutes apart.
Hence , required answer is 56 times .

On 31 st December, 2005 it was Saturday, Number of odd days from the year 2006 to the year 2009
= 1 odd day of 2006 + 1 odd day of 2007 + 2 odd days of 2008 (leap year) + 1 odd day of 2009
= 1 + 1 + 2 + 1 = 5
? On 31st December 2009, it was Thursday
Thus, on 2nd January 2010, it was Saturday .

On the basis of above given question , we know that
400 consecutive years contain 97 leap years.
? In 400 consecutive years February has 29 days 97 times and the remaining 11 months have 29th day
400 × 11 = 4400 times
? 29th day of the month occurs ( 4400 + 97 ) = 4497 times.

As per the above given question , we can say that
Number of days from January 25, 1994 to March 2, 1994 is
January + February + March = 6 + 28 + 2 = 36 days = 5 weeks + 1 odd day
? Number of odd days = 1
? Day on January 25, 1994 is one day before the day on March 2, 1994.
But March 2, 1994 was on Wednesday.
Therefore , January 1994 25 was on Tuesday

As per the given above question , we have
Birth date of Sashikant = September 28
Difference in number of days from August 15 to September 28 = 16 + 28 = 44
Number of odd days in 44 days = 2 odd days
Hence , Birthday of Shashikant = Sunday + 2 odd days = Tuesday.