The year 2008 is a leap year, so it has 2 odd days, 3rd day of the year 2008 was Friday.
? 3rd day of the year 2009 will be 2 days beyond the Friday.
Hence, the required answer is Sunday.
62 -1 = 35, which is divisible by both 5 and 7.
LCM of 16, 18 and 20 = 720
? Required number = 720k + 4
Where, k is a natural number to be divisible by 7, (720 k + 4) will be a multiple of 7.
Smallest value of k = 4
? Required number = 720 x 4 + 4 = 2884
If A Score 100 then B scores 80 and C score 72.
? B scores 80 while C scores 72
? B scores 100 while C scores 72 * 100 / 80 = 90 points
Hence, in 100 points B can give (100 ? 90) = 10 points
Sum of the ages of 4 men five years ago
= 48 x 4
=192 yr
And sum of present ages of the four men
= 192 + 5 x 4
= 212 yr
Now ( 212 + Age of the new man ) / 5 = 50
? Age of the new man = 50 x 5 - 212
= 38 yr.
( 23 - 2) = 6 is the largest natural number that divides ( a3 - a) for every number a.
We know that, a number is divisible by 11 when the sum of the difference between the sum of its digit at even places and sum of its digit at odd places is either 0 or the difference is divisible by 11.
For 93455120
Sum of even places = 3 + 5 + 1 + 0 = 9
Sum of odd places = 9 + 4 + 5 + 2 = 20
There difference = 20 - 9 = 11
which is divisible by 11 so 93455120 is divisible by 11.
Number between 0 and 11 which are multiple of 2 or 3
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
Number between 0 and -11 which are multiple of 2 or 3
= 11/2 + 11/3 - 11/6 = 5 + 3 - 1
= 7
? Number be 15, including 0
Let the number be x.
442 < x < 452
? 1936 < x < 2025 ...(i)
From equation (i), the required number will be any number between 1936 and 2025. Since one part of the number is the square of 6 means one factor is 36.
? L, C, M of 36 and 5 = 180
? Number will be multiple of 180 i,e.,
180 x 11 = 1980 the only value which satisfies the equation (i).
If A run 1000 meters then B runs 900 meters and C runs 800 meters.
? B runs 1350 meters while C will run 800 * 1350/ 900 = 1200 meters
Hence, B can beat C by (1350 ? 1200) = 150 m
S = {HH, HT, TT, TH}
and E = {HH, HT, TH }
? P(E) = n(E)/n(S) = 3/4
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