At what time between 9 o'clock and 10 o'clock, will the hands of a clock be in the same straight line but not together?

Time from 7 am on a day to 6 am after 3 days is 95 h.
Now , 23 h 45 min of the clock in question = 24 h of correct clock
i..e., 95/4 h of the clock in question = 24 h of correct clock
? 95 h of the clock in question = (24 x 4/95 x 95) h of correct clock = 96 h
So, the correct time is 96 h from 7 am, Monday, ie., 7 am, Friday.

Since, angle between two number is 360°/12 = 30°
When the time is 3:25 pm, the minute hand will be at 5 and will have moved 60° from 3 and hour hand would be between 3 and 4 it will move 30° in 60 min and so in 25 min it would have moved 30 x 25/60 = 12.5°
So, angle between two hand will be 60 - 12.5 = 47.5°

Director came at 12 : 15.
Steno came at 12 : 40.
Since, steno was late by 30 min to the meeting.
? Meeting time 12 : 10

The angle between hour hand and minute hand at 5 O'clock = 5 x 30° = 150°
Minute hand move in 10 min = 2 x 30° = 60°
Hour hand move in 10 min = 30°/6 = 5°
? Angle between hour hand and minute hand at 5 h 10 min = 150° - 60° + 5deg; = 95°

1st day of month is Monday.
6th day of month is Saturday.
13th day of month is second Saturday.
17th day is the fourth day after second Saturday.

Given that n = 2 and (n + 1) = 3(n < 6)
The hands will be at the same straight line at
? (5n + 30) x 12/11 min past n.
? (5 x 2 + 30 ) x 12/11 min past 2.
? (10 + 30) x 12/11 min past 2.
? 40 x 12/11 min past 2.
? 480/11 min past 2.

Time from 6 am on a day to 11 pm on 4th day = 89 h
Now, 23 h 44 min of this clock = 24 h of correct clock
89 h of this clock = 24 x (15/356) x 89 h of correct clock = 90 h of correct clock
? Correct time will be 12 o' clock (mid-night).

Time from 9 pm in a day to 2 pm on the following day = 29 h.
24 h 10 min of this clock = 24 h of the correct clock
or 145/6 h of this clock = 24 h of the correct clock
29 h of this clock = 24 x (6/145) x 29 h of the correct clock
= 28 h 48 min of correct clock
? The correct time is 28 h 48 min after 9 am. This will be 48 min past 1.

Given that, time to overtake N = 70 min

The required result = [(720/11) - N) ] x [(60 x 24)/N) min
= [(720/11) - 70) ] x [(60 x 24)/70) min
= [(720 - 770) / 11] x [(60 x 24) / 70] min
= - (50/11) x [(6 x 24)] / 7 min = -7200/77 min
-ve sign indicates that there is a loss.

If the minute hand of a clock overtakes the hour hand at interval N min of the correct time, then clock losses or gains by
The required result = [(720/11) - N) ] x [(60 x 24)/N) min
Positive for gain and negative for loss Here, N = 64

required time = [(720/11) - 64) ] x [(60 x 24)/64) min
= 32⁸/₁₁ min