The number of odd days in a leap year is?

Correct Answer: 1993

Explanation:

Starting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2

So total odd days = 7;
? Calendar for 1993 is the same as that of 1988.

Correct Answer: 73

Explanation:

No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days

Correct Answer: Monday

Explanation:

The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.

? 2nd July, 1984 was Monday

Correct Answer: Thursday

Explanation:

Each day of the week is repeated after 7 days
? After 63 days, it would be Friday
So, After 62 days, it would be Thursday

Correct Answer: 1997

Explanation:

For two years having same calendar must have two common conditions: both having same length in terms of number of days and first day of the week.

The year 1991 has 365 days,,that is 1 odd day , year 1992 has 366 days , i.e. 2 odd days , year 1993 has 365 days i.e. 1 odd day. the years 1994,1995,1996 have 1 odd day each.

the sum of odd days so calculated from year 1990 to 1996 .
(1+2+1+1+1+1)=7 odd days. 5

hence, the year 1997 will have same calendar as that of year 1990.

Correct Answer: 13 h and 48 min

Explanation:

Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h
and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min
? Total hours and minutes = 12 h + 1 h 48 min
= 13 h and 48 min

Correct Answer: 164/11 min past 3

Explanation:

Here, n = 3 and (n + 1) = 4
? Two hands will coincide at 60n / 11 min past n
? 60 x 3 / 11 min past 3
? 180 /11 min past 3.
? 16⁴/Sub>11 min past 3

Correct Answer: 4

Explanation:

A leap year must be divisible by 4 as every 4th year is a leap year..

Correct Answer: 2008

Explanation:

Count the number of odd days from the year 2002 onwards to get the sum equals to 0 odd day.

Years 2002 2003 2004 2005 2006 2007
Odd days 1 1 2 1 1 1

Sum = 7 odd days = 0 odd day
Calender for the year 2008 is the same as that for the year 2002.

Correct Answer: 2800

Explanation:

The century year which is completely divisible by 400, is a leap year. Thus, the year 2800 is a leap year.