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- Question
- The year next to 1990 having the same calender as 1998 is?
Options- A. 1990
- B. 1992
- C. 1993
- D. 1995
- Correct Answer
- 1993
ExplanationStarting with 1988, we go on counting thye number of odd days till the sum is divisible by 7
Year 1988 odd days = 2
Year 1989 odd days = 1
Year 1990 odd days = 1
Year 1991 odd days = 1
Year 1992 odd days = 2
So total odd days = 7;
? Calendar for 1993 is the same as that of 1988. - 1. How many days are three from 2nd January 1993 to 15th march 1993?
Options- A. 72
- B. 73
- C. 74
- D. 71 Discuss
- 2. On July, 2, 1985, it was Wednesday the day of the week on July 2, 1984 was?
Options- A. Wednesday
- B. Tuesday
- C. Monday
- D. Thurdays Discuss
- 3. Today is Friday. After 62 days it will be?
Options- A. Friday
- B. Thursday
- C. Saturday
- D. Monday Discuss
- 4. The year next to 1991 will have the same calender as that of the year 1991.
Options- A. 1992
- B. 1995
- C. 1996
- D. 1997 Discuss
- 5. The ratio of ages of Mohan and Sohan is 3 : 4. Four years ago the ratio was 5 : 7. Find the present ages of Mohan and Sohan.
Options- A. 24 years, 32 years
- B. 20 year, 30 years
- C. 25 years, 30 years
- D. None of these Discuss
- 6. The number of odd days in a leap year is?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 7. Number of hours and minutes from 6 : 14 am to 8 : 02 pm on the same days is?
Options- A. 2 h and 12 min
- B. 12 h and 16 min
- C. 13 h and 48 min
- D. 14h and 16 min Discuss
- 8. At what time between 3 o'clock and 4 o'clock will the hands of a clock be together?
Options- A. 163/11 min past 3
- B. 143/11 min past 3
- C. 132/11 min past 3
- D. 164/11 min past 3 Discuss
- 9. By which of the following a leap year must be divided
Options- A. 9
- B. 6
- C. 5
- D. 4 Discuss
- 10. The calendar for the year 2002 is the same as for the year
Options- A. 2006
- B. 2008
- C. 2009
- D. 2010 Discuss
Calendar problems
Search Results
Correct Answer: 73
Explanation:
No of days = Jan. + Feb. + March
30 + 28 + 15 = 73 days
Correct Answer: Monday
Explanation:
The year 1984 being a leap year, it has 2 odd days. So, the day on 2nd July, 1985 is two days beyond the day on 2nd July, 1984. But, 2nd July 1985 was Wednesday.
? 2nd July, 1984 was Monday
Correct Answer: Thursday
Explanation:
Each day of the week is repeated after 7 days
? After 63 days, it would be Friday
So, After 62 days, it would be Thursday
Correct Answer: 1997
Explanation:
For two years having same calendar must have two common conditions: both having same length in terms of number of days and first day of the week.
The year 1991 has 365 days,,that is 1 odd day , year 1992 has 366 days , i.e. 2 odd days , year 1993 has 365 days i.e. 1 odd day. the years 1994,1995,1996 have 1 odd day each.
the sum of odd days so calculated from year 1990 to 1996 .
(1+2+1+1+1+1)=7 odd days. 5
hence, the year 1997 will have same calendar as that of year 1990.
Correct Answer: 24 years, 32 years
Explanation:
Let us assume the present ages of Mohan and Sohan be 3x years and 4x years; then,
4 Four years ago the ages was 3x - 4 and 4x - 4 years.
According to question, 4 Four years ago the ratio was 5 : 7
( 3x - 4 ) / ( 4x - 4 ) = 5/7
? ( 3x - 4 ) 7 = 5 ( 4x - 4 )
? 21x - 28 = 20x - 20
? 21x - 20x = 28 - 20
? x = 8
Hence, their present ages, 3x = 3 x 8 = 24 years; 4x = 4 x 8 = 32 years.
So their present ages 24 and 32 years.
Correct Answer: 2
Explanation:
A leap year has (52 week + 2 days).
So, the number of odd days in a leap year is 2
Correct Answer: 13 h and 48 min
Explanation:
Total hours 6 : 14 am morning to evening 6 : 14 pm = 12 h
and total hours from 6 : 14 pm evening to 8 : 02 pm evening = 8 : 02 - 6 : 14 = 1 : 18 h i.e., 1 h and 48 min
? Total hours and minutes = 12 h + 1 h 48 min
= 13 h and 48 min
Correct Answer: 164/11 min past 3
Explanation:
Here, n = 3 and (n + 1) = 4
? Two hands will coincide at 60n / 11 min past n
? 60 x 3 / 11 min past 3
? 180 /11 min past 3.
? 164/Sub>11 min past 3
Correct Answer: 4
Explanation:
A leap year must be divisible by 4 as every 4th year is a leap year..
Correct Answer: 2008
Explanation:
Count the number of odd days from the year 2002 onwards to get the sum equals to 0 odd day.
Years 2002 2003 2004 2005 2006 2007
Odd days 1 1 2 1 1 1
Sum = 7 odd days = 0 odd day
Calender for the year 2008 is the same as that for the year 2002.
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