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- Question
- 15 years later, A will be twice as old as B but five years ago A was 4 times as old as B. Find the difference of their present ages?
Options- A. 15 years
- B. 45 years
- C. 30 years
- D. 25 years
- Correct Answer
- 30 years
ExplanationLet A's age = x years and B's age = y years
As per the first condition,
? (x + 15) = 2(y + 15)
? x - 2 y = 15 ....(i)
As the per second condition,
? (x - 5) = 4(y - 5)
? x - 4 y = -15 ....(ii)
Solving (i) and (ii) one get's, x = 45, y = 15
? A's age = 45 years
B's age = 15 years
? Difference of their ages = 45 - 15 = 30 years - 1. A says to B "I am twice as old as you were when I was as old as you are." The sum of their ages is 63 years. Find the difference of their ages?
Options- A. 27 years
- B. 12 years
- C. 9 years
- D. 6 years Discuss
- 2. A is as much younger than B as he is older then C. If the sum of B's and C's age is 40 years. Find the age of A.?
Options- A. 20 years
- B. 25 years
- C. 30 years
- D. 27 years Discuss
- 3. Five years ago, the total of the ages of father and son was 60 years. The ratio of their present ages is 4 : 1. Then the present age of the father is?
Options- A. 48 years
- B. 51 years
- C. 56 years
- D. 61 years Discuss
- 4. Two years ago, a mother was four times as old as her daughter. 8 years later, mother's age will exceed her daughter's age by 12 years. The ratio of the present ages of mother and daughter is?
Options- A. 3 : 1
- B. 4 : 1
- C. 3 : 2
- D. 5 : 1 Discuss
- 5. If C's age is twice the average age of A, B and C, A's age is one half the average of A, B and C. If B is 5 years old, the average age of A, B and C is?
Options- A. 10 years
- B. 15 years
- C. 12 years
- D. 9 years Discuss
- 6. The ratio of the present ages of a son and his father is 1 : 5 and that of his mother and father is 4 : 5. After 2 years the ratio of the age of the son to that of his mother becomes 3 : 10. What is the present age of the father?
Options- A. 30 years
- B. 28 years
- C. 27 years
- D. None of these Discuss
- 7. The product of the ages of Harish and Seema is 240 . If twice the age of seema is more then Harish's age by 4 years. What is seema's age in years?
Options- A. 12 years
- B. 20 years
- C. 10 years
- D. 14 years Discuss
- 8. If the age of P and R are added to twice the age of Q the total becomes 59. If the ages of Q and R are added to thrice the age of P the total becomes 68. And if the age of P is added to thrice the age of Q and thrice the age of R, the total becomes 108. what is the age of P T?
Options- A. 15 years
- B. 19 years
- C. 17 years
- D. 12 years Discuss
- 9. After 6 years Pradhan's age will be 3/7 times the age of his father. 10 years ago the ratio in the age of Pradhan and his father was 1 : 5. What is the present age of Pradhan's father?
Options- A. 40 years
- B. 50 years
- C. 56 years
- D. Data is inadequate Discuss
- 10. The ratio between present age of Kunal and Ganesh is 3 : 5. If 4 years later Kunal will be younger then Ganesh by 12 years. What is the present age of Kunal?
Options- A. 17 years
- B. 19 years
- C. 22 years
- D. None of these Discuss
Problems on Ages
Search Results
Correct Answer: 9 years
Explanation:
Let the present age of A is x and present age of B is y.
Therefore, x + y = 63 ....(i)
Difference of their ages is = (x - y) years.
When A was as old as B then, A's age was 'y; years and B's age was [y - (x - y)] = (2y - x) years.
Given that present age of A is twice the past age of B.
? x = 2(2y - x)
? 3x = 4y .....(ii)
From (i) and (ii)
x = 36 and y = 27
So the difference in age of A and B is 36 - 27 = 9 years.
Correct Answer: 20 years
Explanation:
Age of C < Age of A < Age of B
From question,
A = C + x ....(i)
B = A + x ....(ii)
From equation (i) and (ii)
A - B = C - A
? 2A = B + C
? A = (B + C) / 2
Given that sum of the ages of B and C is 40 years.
So, A = (B + C) / 2 = 40/2 = 20 Years
Correct Answer: 56 years
Explanation:
Let the present age of the son be x and that of the father be 4x years.
? (x - 5) + (4x - 5) = 60
? 5x = 70
? x = 14 years
? Father's present age = 4x = 56 years
Correct Answer: 3 : 1
Explanation:
Let the mother's age 2 years ago be 4x and daughter's age 2 years ago be be x.
? (4x + 8) - (x + 8) = 12
? 3x = 12
? x = 4
? Mother's present age = 4x + 2 = 18 years
and daughter's present age = x + 2 = 6 years
? Required ratio = 3 : 1
Correct Answer: 10 years
Explanation:
Let the average age of A, B and C be N years.
? Total age of A, B and C = 3 x N = 3N years
Now, according to the question,
? 3N - (2N + N/2) = 5
? N = 10 years.
Correct Answer: None of these
Explanation:
? S / F = 1 / 5
? F = 5 S, .....(i)
? M / F = 4 / 5
? M = 4 / 5 F ....(ii)
? (S + 2) / (M + 2) = 3 / 10
? 10S + 20 = 3M + 6 ....(iii)
From (i), (ii) and (iii)
? (12 - 10)S = 20 - 6
? 2S = 14
? S = 7 years
? F = 5S = 5 x 7 = 35 years.
Correct Answer: 12 years
Explanation:
Let the ages of Harish and Seema be x and y respectively.
According to the question,
xy = 240 ....(i)
2y - x = 4 ....(ii)
Solving equations (i) and (ii), we get
y = 12 years
Correct Answer: 12 years
Explanation:
P + R + 2 Q = 59, ....(i)
Q + R + 3 P = 68 .....(ii)
and P + 3 (Q + R) = 108 ......(iii)
Solving the above three equations, we get
? P + 3 (68 - 3P) = 108
? P + 204 - 9P = 108
? P = 12 years.
Correct Answer: 50 years
Explanation:
Let the present age of Pradhan be P years and his father's age = Q years.
From 1st condition,
(P + 6) = (Q + 6 ) x 3/7
? 7P + 42 = 3Q + 18
? 7P - 3Q = -24 ...(i)
From 2nd condition
(P - 10) / (Q - 10) = 1/5
? 5P - 50 = Q - 10
? 5P - Q = 40 .....(ii)
Multiplying equation (ii) by 3 and subtracting from (i) we get
P = 18, Q = 50
So present age of Pradhan's father = 50 years.
Correct Answer: None of these
Explanation:
Let the present age of Kunal be 3x year and the
present age of Ganesh = 5x years.
According to question ,
(5x + 4 ) - (3x + 4 ) = 12
? 2x = 12
? x = 6
? Present age of Kunal = 3x = 3 x 6 = 18 year
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