Let TD = N, then BD = 11N/10
Sum = (BD x TD) / (BD - TD) = [(11N/10) x N] / [11N/10 - N]
= [11N2/10] / [N/10] = 11N
SI on ? 11N for 4 yr is ? 11N/10.
? Rate = (100 x 11N/10)/(11N x 4)% per annum
= 2.5% per annum
The shaded region represents
y ? x
Let 45 x A = (25 x 900)/100
? A = (25 x 9)/45 = 5
CP = [100/(100 - Loss%) ] x SP
CP = 6000 x (100/75) = 8000
NA
Angle swept in 30 min= 180°
Area swept = [(22/7) x 7 x 7] x [180°/360°] cm2
= 77 cm2
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