Let time taken to cover the distance = t
? Speed = (2t + 1)
? t(2t + 1) = 1830 ? 2t2 + t = 1830
? 2t2 + t - 1830 = 0
? t = -1 ± ?(1)2 - 4 x 2 x(-1830) / 2 x 2
= -1 ± ?1 + 14640 / 4
= -1 ± 121 / 4
Taking '+' sign t = -1 + 121 / 4 = 120/4 = 30
? Required ratio = (2 x 30 + 1) : 30 = 61 : 30
120 = (3000 x 6) / (Ans - 0)
? Ans = (3000 x 6) / 120 = Rs. 150
Sum of the age of 45 students = 45 x 13 = 585 yr
Sum of the age of 15 students = 15 x18 = 270 yr
Sum of the age of all students = sum of the age of 45 students + sum of the age of 15 students
= 585 yr + 270 yr
=855 yr
? Average age of all students = 855 ? 60
= 14.25 yr
Let the average of 14th innings = x
? Average of 15th innings = x+2
Then, 14x+72 = 15(x+2)
? 14x+72 = 15x +30
? x = 42
? Average for 15th innings = x+2 = 42 + 2 = 44
Principal = Rs. | ❨ | 100 x 5400 | ❩ | = Rs. 15000. |
12 x 3 |
CP per kg of the mixture = (w1x1 + w2x2 + w3x3) / (w1 + w2 + w3)
= (7 x 72 + 33 x 87 + 35 x 85)/75
= (504 + 2871 + 2975)/75 = 6350/75 = ? 84.66
Profit = 15%
? SP per kg = ? 84.66 + 15% of ? 84.66
= ? 97.37
race remains to be run = 5 - 5?4 = 15?4 .
16 | 2 | % |
3 |
14 | 1 | % |
2 |
13 | 1 | % |
3 |
16 | 2 | % |
3 |
S.P. = 102% of Rs. 600 = | ❨ | 102 | x 600 | ❩ | = Rs. 612. |
100 |
Now, P.W. = Rs. 612 and sum = Rs. 688.50.
∴ T.D. = Rs. (688.50 - 612) = Rs. 76.50.
Thus, S.I. on Rs. 612 for 9 months is Rs. 76.50.
∴ Rate = | ❨ | 100 x 76.50 | ❩% | = 16⅔% |
|
The value of | ( | - |
|
) | -(2/3) |
125 |
(4 x 4 x 4 x 4 x 4 x 4)5 x (4 x 4 x 4)8 ÷ (4)3 = (64)?
? (46)5 x (43)8 x 1/(4)3 = (43)?
? (4)30 x (4)24/(4)3 = (4)3 x ?
? 430 + 24 - 3 = 43 x ?
? 451 = 43 x ? ? 3 x ? = 51
? ? = 51/3 = 17
Let the number be N.
According to question,
A number is doubled and 9 is added then 2N + 9
Again According to question,
If the resultant is tripled, it becomes 75.
3 ( 2N + 9 ) = 75
? 2N + 9 = 25
?2N =16
? N = 8
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