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- Question
- Den Bosh and Eastbourne are two famous cities 300 km apart. Maradona starts from Den Bosch at 8 : 24 am. An hour later Pele starts from Den Bosch. After travelling for 1 hour, Pele reaches Nottingham that Maradona had passed 40 minutes earlier. Nottingham falls on the way from Den Bosh to Eastbourne at the same time, what is the speeds of the time Maradona and Pele respectively?
Options- A. 100 km/h, 125 km/h
- B. 60 km/h, 80 km/h
- C. 60 km/h, 75 km/h
- D. 75 km/h, 100 km/h
- Correct Answer
- 75 km/h, 100 km/h
ExplanationLet pele covers D km in 1 hours. So Maradona takes (2 h - 40 min) = 1 h 20 min to cover D km.
Let speed of Maradona and pele be M and P respectively than.
D = M x 4/3 and D = P x 1
M/P = 3/4
Again, 300/M - 300/P = 1
300/3k - 300/4k = 1
k = 25
M = 3k = 75 km/h and
P = 4k = 100 km/h - 1. A thief sees a jeep at a distance of 250 m, coming towards him at 36 km/h. Thief takes 5 seconds to realise that there is nothing but the police is approaching him by the jeep and start running away from police at 54 km/h. But police realise after 10 seconds, when the thief starts running away, that he is actually a thief and gives chase at 72 km/h. how long after thief saw police did police catchup with him and what is the distance police had to travel to do so?
Options- A. 50 sec, 1000 m
- B. 65 sec, 1150 m
- C. 65 sec, 1300 m
- D. 45 sec, 1050 m Discuss
- 2. In a circus there was a leopard and a tiger walking in the two different rings of same radii. There I observed that when leopard moved 3 steps, tiger moved 5 steps in the same time,but the distance traversed by leopard in 5 step is equal to the distance traversed by tiger in 4 steps. what is the number of rounds that a leopard made when tiger completed 100 rounds?
Options- A. 120
- B. 48
- C. 75
- D. none of these Discuss
- 3. Two car A and B are running toward each other from two different place 88 km apart. If the ratio of the speed of the car A and B is 5:6 and the speed of the car B is 90 km per hour, after how long will the two meet each other?
Options- A. 26 min.
- B. 24 min.
- C. 32 min.
- D. 36 min. Discuss
- 4. Two boys begin together to write out a booklet containing 817 lines. The first boy start with first line, writing at rate of 200 lines an hour and the second boys start with a last line. He writes line 817 and so on backwards proceeding at the rate of 150 lines an hour. An what line will they meet?
Options- A. 466th
- B. 465th
- C. 467th
- D. 468th Discuss
- 5. A start from P walk to Q a distance of 51.75 kilometer at the rate of 3.75 km an hour. An hour latter B starts from Q for P and walk at the rate of 4.25 km an hour. When and where will A meet B?
Options- A. 26.25 km. from Q
- B. 25.50 km. from Q
- C. 25.30km. from P
- D. can't be determined Discuss
- 6. Soniya and Priyanka started from Amethi and Bellari for Bellari and Amethi, which are 645 km apart. They meet after 15 hours. After their meeting, Sonia increased her speed by 3 km/h and priyanka reduced her speed by 3 km/h, they arrived at Bellari and Amethi respectively at the same time. What is their initial speeds?
Options- A. 24 km/h and 30 km/h
- B. 25 km/h and 18 km/h
- C. 18 km/h and 21 km/h
- D. 20 km/h and 23 km/h Discuss
- 7. A tiger is 50 of its own leaps behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 m and 5 m per leap respectively, what distance will the tiger have to run before it catches the deer?
Options- A. 600 m
- B. 700 m
- C. 800 m
- D. 1000 m Discuss
- 8. Akbar and Birbal setout at the same time to walk towards each other respectively from Agra and Banaras 144 km apart. Akbar walks at the constant speed of 8 km/h, while Birbal walks 4 km in the first hour, 5 km in the second hour, 6 km in the third hour and so on. Then the Akbar and Birbal will meet?
Options- A. In 6 hr.
- B. In 8 hr.
- C. Midway between Agra and Banaras
- D. 80 km away from Banaras Discuss
- 9. Amarnath express left Amritsar for Gorakhpur. Two hours later Gorakhnath express left from Amritsar to Gorakhour. Both trains reached Gorakhpur simultaneously. If Amarnath express had started from Amritsr and Gorakhnath express had started from Gorakhpur at the same time and travelled towards each other they would meet in 1 h 20 min. Find the time taken by Amarnath express to travel from Amritsar to Gorakhpur(in hour)?
Options- A. 2
- B. 4
- C. 5
- D. 6 Discuss
- 10. A man goes to the fair in Funcity with his son and faithful dog. Unfortunately man misses his son which he realises 20 minutes later. The son comes back towards his home at the speed of 20 m/min and man follows him at 40 m/min. The dog runs to the son (child) and comes back to the man (father) to show him the direction of his son. It keeps moving to and fro at 60 m/min between son and father, till the man meets the son. what is the distance travelled by the dog in the direction of the son?
Options- A. 800 m
- B. 1675 m
- C. 848 m
- D. 1000 m Discuss
Time and Distance problems
Search Results
Correct Answer: 65 sec, 1150 m
Explanation:
Initial speed of police = 10 m/s
Increased speed of police = 20 m/s
Speed of thief = 15 m/s
Initial difference between thief and police = 250 m
After 5 seconds difference between thief and police = 250 - (5 x 10) = 200 m
After 10 seconds more, the difference between thief and police = 200 + (5 x 10) = 250 m.
Now, the time required by police to catch the thief = 250/5 = 50 s
Distance travelled = 50 x 20 = 1000 m
Total time = 50 + 15 = 65 sec
Total distance = 1000 + (15 x 10) = 1150 m
Correct Answer: 48
Explanation:
The ratio of speeds = The ratio of distances, when time is constant
? The ratio of distance covered by leopard to the tiger = 12 : 25
Again, ratio of rounds made by leopard to the tiger = 12 : 25
hence, leopard makes 48 rounds, when tiger makes 100 rounds
Correct Answer: 32 min.
Explanation:
Speed of the car A = (5 / 6) x 90
= 75 km/hr.
? Required time = [ 88 / (90 +75)] x 60
= 32 minutes
Correct Answer: 467th
Explanation:
Let the two meet at the Nth line
From the question
Nth/200 = (817 - Nth)/150
? 3Nth = 4(817-Nth)
? Nth = (4 x 817) / 7
? Nth = 466.85
So, they will meet at the 467th line
Correct Answer: 25.30km. from P
Explanation:
A has already gone 3.75 km when B starts of the remaining 48 km.
A walks 3.75 km and B walks 4.25 km in one hour in opposite direction i.e., they together pass over (3.75 + 4.25) = 8 km. in hour.
Therefore , 48 km. are passed over in 48/8= 6 hours.
? A meets B in 6 hours after B started and, therefore, they meet at a distance of (4.25 X 6 ) = 25.5km. from Q.
Correct Answer: 20 km/h and 23 km/h
Explanation:
The sum of their speeds = 615/15 = 43 km/h
Notice that they are actually exchanging their speeds. Only then they can arrive at the same time at their respective destinations.It means the difference in speeds is 3 km/h.
Thus, x + ( x + 3) = 43
x = 20 and x + 3 = 23
The concept is very similar to the case when after meeting each other they returned to their own places of departure. It can be solved through option also.
Correct Answer: 800 m
Explanation:
Speed of tiger = 40 m/min
Speed of dear = 20 m/min
Relative speed = 40 - 20 = 20 m/min
Difference in distance = 50 x 8 = 400 m
? Time taken in overtaking (or catching) = 400/20 = 20min
? Distance travelled in 20 min = 20 x 40 = 800 m
Correct Answer: Midway between Agra and Banaras
Explanation:
Distance travelled by them in first hour = 12 km
Distance travelled by them in second hour = 13 km
Distance travelled by them in third hour = 14 km and so on
Thus in 9 hours they will cover exactly 144 km and in 9 h each will cover half the total distance.
( 8 x 9 = 72 and 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 = 72)
Correct Answer: 4
Explanation:
Let Amarnath express takes H hours, then Gorakhnath express takes (H - 2) hours.
? 1/H + 1/(H - 2) = 60/80
H = 4 hrs.
Correct Answer: 1000 m
Explanation:
In 20 minutes the difference between man and his son = 20 x 20 = 400 m
Distance travelled by dog when he goes towards son = (400/40) x 60 = 600 m and time required is 10 minutes
In 10 minutes the remaining difference between man and son = 400 - (20 x 10) = 200 m
Note: Relative speed of dog with child is 40 km/h and the same with man is 100 km/h.
Time taken by dog to meet the man = 200/100 = 2 min
In 2 minute the remaining distance between child and man = 200 - ( 2 x 20) = 160 m
Now, the time taken by dog to meet the child again = 160/40 = 4 min
In 4 minutes he covers 4 x 60 = 240 m distance while going towards the son.
In 4 minute the remaining distance between man and child = 160 - (4 x 20) = 80 m
Time required by dog to meet man once again = 80/100 = 0.8 min
In 0.8 min remaining distance between man and child = 80 - (0.8 x 20) = 64 min
Now, time taken by dog to meet the child again = (64/40) x (8/5) min
? Distance travelled by dog = (8/5) x 60 = 96 m
Thus, we can observe that every next time dog just go 2/5th of previous distance to meet the child in the direction of child.
So, we can calculate the total distance covered by dog in the direction of child with the help of GP formula.
Here, first term (a) = 600 and common ratio (r) = 2/5
Sum of the infinite GP = a/(1 - r)
= 600/(1 - 2/5) = (600 x 5)/3 = 1000 m
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