Let time taken by A = Y
Let speed of C = x
Then, speed of B = 3x
? speed of A = 6x
Now, ratio of speeds of A and C = Ratio of time taken by C and A
6x : x = 56 : y
? 6x/x = 56/y
? y = 56/6 = 92/6
= 91/3 min
Let the length of each train = L metres
Relative speed = (46 - 36) = 10 km/hr. = 10 x (5/18) = 25/9 m/sec
Distance covered in crossing = (L + L) = 2L metres
? 2L x (9/25) = 36
? L = (25 x 36)/(2 x 9) = 50 metres.
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