Average speed = 2ab/(a+b)
= (2 x 4 x 6)/(4 + 6)
= 48/10
= 4.8 km/h
Sd = 12 km/h
Su = 5 km/h
Speed of current = (12 - 5)/2 = 3.5 km/h
W + R = 4 h 20 min
W + W = 5 h 20 min
? R + R = 3 h 20 min
Speed of the motor car in meter per second = 250 / 25
= 10 m/s
Speed in km/hr = (18/5) x speed in m/s
= 10 x (18 / 5) km/hour
=36 km/hour.
speed of a train in kilometer per hour =45
Speed in meter per second = ( 5/18 ) x Speed in kilometer per hour
= 45 x 5/18
= 12.5 kmph
At 3/4 of the usual speed, the time taken is 4/3 of the usual time
? 4/3 of usual time - usual time = 20 min
? 4x/3 - x = 20
? x/3 = 20
? x = 60 min.
Average speed of entire journey
= (39 + 39 + 39)/(39/26 + 39/39 +39/52)
= 3/(1/26 + 1/39 +1/52)
= 3/[(6 + 4 + 3)/156]
= 3 x 156/13 = 36 km/h
? 1 m/s = 18/5 km/h
? 31/3 m/s = 10/3 m/s = (10/3) x (18/5) km/h
= 12 km/h
We know that, speed = Distance / Time
? Required speed = 300/15 =20 km/h
Required speed = Distance/ Time
= 690/30
= 23 km/h
We know that, Speed = Distance / Time
? Required distance = Speed x Time
= 37 x 8 = 296 km
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