25 men and 15 women can complete, a piece of work in 12 days.
? Work done by them in 8 days = 8/12 = 2/3
Remaining work is completed by 25 men in 6 days
? Time taken by 25 men to complete the whole work = 3 x 6 = 18 days
From the question
Time taken by 15 women to complete the whole work = 1 / (1/12 - 1/18)
= 1 / {(3 - 2) / 36} = 36/(3 - 2) = 36 days
Efficiency ( per minute) of Modi = 4 copies/min
Efficiency of Modi and Xerox together = 10 pages/min
? Efficiency of Xerox alone = 10 - 4 = 6 pages/min
? Mr. Xerox needs 6 min to copy 36 pages.
Y = 56 x (27/23) x (552/448)
=81
Extra men required =81-56
=25
A,s 1 days work =1/8
B's 1 day's work in breaking the building = 1/3
Now, according to the question,
A's 4 day's work = 4 x (1/8) = 1/2
Now, A's and B's 2 day's work
= 2[(1/8) - (1/3)] = 2 x (-5/24) = -10/24
Total work done in 6 days = 1/2 + (-10/24) = (12 - 10)/24 = 2/24 = 1/12
Remaining work = 1 - (1/12) = 11/12
Now, A has complete the work, so A can complete in N days.
(1/8) x N = 11/12
? N = (11 x 8) / 12
N = (11 x 2)/3 = 71/3 days
(A + B)'s 2 day's work = (1/12) + (1/18) = 5/36
(A + B)'s 14 day's work = (5/36) x 7 = 35/36
Remaining work = 1 - (35/36) = 1/36
Now, it is the turn of A .
A's 1 day's work = 1/12
? 1/36 work is done by A in 12 x (1/36) days = 1/3 days
? Total time taken = 141/3 days
Here, a1 = 8, b1 = 4, a2 = 1, b2 = 1 and n = 7
? Work done by 1 man/Work done by 1 boy = (nb2 - b1)/(a1 - na2)
= (7 x 1 - 4) / (8 - 7 x 1)
= 3
As per question, work of A for 1 day = 1/12 and work of B for 1 day = 1/8
? Work of (A + B) together for 1 day = 1/12 + 1/8 = (2 + 3)/24 = 5/24
? Work of (A + B) together for 3 days = 3 x (5/24) = 5/8
? Remaining work after 3 days = 1 - 5/8 = 3/8
? C can do the same work in = 4/5th time required by (A + B) = 4/5 x 24/5 = 96/25 days
? Work of C for 1 day = 25/96 part.
? 25/96 part work can be done by C in 1 day
? 3/8 part work can be done by C in = 96/25 x 3/8 days = 36/25 days = 111/25
? The complete day C did the work = 1 day.
Work of A for 1 day = 1/15
Work of B for 1 day = 1/20
Work of (A + B) together for 1 day = 1/15 + 1/20 = (4 + 3)/60 = 7/60
Remaining work after A alone does for 1 day = 1 - 1/15 = 14/15
? 7/60 part-work can be complete by (A + B) in 1 days
? 14/15 part-work can be completed by (A + B) in = (60/7) x (14/15) = 8 days.
(A + B)'s 5 day's work = 5 x (1/10 + 1/20) = 3/4
Remaining work = (1 - 3/4) = 1/4
1/20 work is done by B in = 1 day
? 1/4 work is done by B in = 20 x (1/4) i.e., 5 days.
1 men's one day's work = 1/96
12 men's 3 day's work = 3 x (1/8) = 3/8
Remaining work = (1 - 3/8) = 5/8
15 men's 1 day's work = 15/96
Now, 15/96 work is done by them in 1 day
? 5/8 work will be done by them in = (96/15) x (5/ 8) i.e., 4 days
(B + C)'s 2 day's work = 2 x (1/10 + 1/15) = 1/3
Remaining work = (1 - 1/3) = 2/3
? 1/9 work is done by A in 1 day
? 2/3 work is done by A in (9 x 2) / 3 = 6 days
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.