Mixed-team productivity then women-only completion Twenty-five men and fifteen women can complete a job in 12 days. All begin together; after 8 days the women stop. The remaining work is finished by 25 men in 6 days. How long would it take if only 15 women worked from start to finish?

Introduction / Context:This is a two-phase workforce problem used to infer relative productivities of men and women. After learning the ratio, compute the total work in man-rate units and then find the women-only duration.

Given Data / Assumptions:

• Phase 1: (25 men + 15 women) for 8 days, then women leave.
• Phase 2: 25 men alone finish the remainder in 6 days.
• Productivity is linear and constant.

Concept / Approach:Let man rate = m and woman rate = w (jobs per day). Equate Phase-2 remainder to solve for w in terms of m, then compute total job in m-units and divide by 15w.

Step-by-Step Solution:

Verification / Alternative check:36 days is consistent with the inferred m:w ratio 6:5 and total job size 450m.

Why Other Options Are Wrong:60, 88, 94 do not match the derived 36 days. Hence the correct choice within the given set is “None of these.”

Common Pitfalls:Assuming the total work is 12 days of the mixed team without converting to rates; or forgetting to scale by 15w for the women-only case.

Final Answer:None of these