Given, M1 = 40, W1 = 200, T1 = 8, D1 = 12,
M2 = 30, W2 = 300, T2 = 6 and D2 = ?
Then, using formula
M1T1D1W2 = M2T2D2W1
? 40 x 8 x 12 x 300 = 30 x 6 x D2 x 200
? D2 = (40 x 8 x 12 x 300)/(30 x 6 x 200) = 32 days.
Given, M1 = 20, T1 = 4, W1 = 30,
M2 = 20 - 4 = 16, T2 = 12 and W2 = ?
According to the formula,
M1T1W2 = M2T2W1
? 20 x 4 x W2 = 16 x 12 x 30
? W2 = (16 x 12 x 30)/(20 x 4) = 12 x 6 = 72 trees
Given, M1 = 12, M2 = 8 , D1 = 24 , W1 = 1, W2 = 1
According to the formula,
M1D1W2 = M2D2W1
? 12 x 24 x 1= 8 x D2 x 1
? D2 = (12 x 24)/8
= 12 x 3 = 36 days
Given, M1 = 20 D1 = 7, M2 = 20 + 8 = 28
and D2 = ?
Using formula, M1D1 = M2D2
? 20 x 7 = 28 x D2
? D2 = (20 x 7)/28 = 5 days
Here A = 60 days, B = 75 days, D = 30, T = ?
? Required time = (B - D) x [A/(A + B)]
= (75 - 30) x [60/(60 + 75)]
= (45 x 60)/135 = 20 days
? Required time = 20 days
(P + Q)'s 10 day's work= (1/30) x 10 = 1/3
Remaining work = (1 -1/3) = 2/3
2/3 work is done by P in 20 days.
? Whole work is done by P in 20 x (3/2) = 30 days
Let the required number of units of work = k
According to the formula,
W1= m and W2 = k
M1T1D1W2 = M2T2D2W1
? m x m x m x k = n x n x n x m
? x= (m x n3) / m3 = n3/m2
Given, M1 = 20.
M2 = 20 + k
W1 = 1/3, W2 = 1 - 1/3 = 2/3
D1 = 20 and D2 = 25
According to the formula,
M1D1W2 = M2D2W1
? 20 x 20 x (2/3) = (20 + k) x 25 x 1/3
? 20 x 20 x (2/3) = (20 + k) x 25/3
? 16 x 2 = 20 + k
? k = 32 - 20 = 12
Given, M1 = 45, D1 = 18, M2 = ? , D2 = 15
By using the formula,
M1D1 = M2D2
? M2 = M1D1/D2
? M2 = (45 x 18)/15 = 3 x 18
? M2 = 54
3 men = 4 women
? 1 man = 4/3 women
? 7 men + 5 women = 7 x (4/3) + 5 = 43/3 women
? M1D1W2 = M2D2W1
? 4 x 43 x 1 = (43/3) x D2 x 1
? D2 = 3 x 4 = 12 days
(A+ B )' s 1 day ' s work = 1/18
(B +C )'s 1 day ' s work = 1/24
(C + A) 's 1 day 's work = 1/36
From Eqs. (i), (ii) and (iii), we get
2(A + B + C)' s 1 day 's work = 1/18 + 1/24 + 1/36
(A + B + C)'s 1 day's work = (4 + 3 + 2)/(72 x 2)
= 9/(72 x 2) = 1/16
? (A + B + C) can complete the work in 16 days
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