Efficiency of A = 4.16%
Efficiency of B = 1.6 x 4.16 = 6.66%
? Number of days required by B = 100/6.66 = 15 days
One day's work of A and B = 1/14 + 1/21 = 5/42
? Required number of days = 42/5 = 8.4 days
Efficiency of A = 100/12 = 8.33%
Efficiency of B = 100/15 = 6.66%
Combined efficiency of A and B = 8.33 + 6.66 = 15%
Number of days taken by A and B, when worked together = 100/15
= 62/3 days
A's 1 day's work = 1/12
B's 1 day's work = 1/12 + 60% of 1/12 = 1/12 x 160/100 = 2/15
? B can do the work in 15/2 days = 71/2 days.
Required time taken to complete the work by both together = x y / x + y
(Here x = 8 and y = 4)
? Required time = (8 x 4)/(8 + 4) = 32/12 = 22/3 hours
Required time taken by B to complete the work = xy / x - y
[Here x = 12 and y = 8]
? required time = (12 x 8) / (12 - 8) = 96/4 = 24 days
One day's work of A and B = 1/x + 1/2x = 1/14
? x = 21
Since A is twice efficient as B so A will take half of the day taken by B.
Efficiency of Ajit : Bablu = 3 : 1
No. of days 1 : 3
Efficiency (X : Y) = 5 : 1
No. of days (X : Y) = 1 : 5
Efficiency of Sonu = (100/20) = 5%
Rest work = 75%
? Efficiency of Abhijeet = 75/10 = 7.5%
? Combined efficiency of Sonu and Abhijeet = 7.5 + 5 = 12.5%
? Number of days required by Sonu and Abhijeet, to work togethere = 100/12.5 = 8days
Work of (A + B + C) in 1 H = 1 / 6
Work done in 2 h = 2/6 = 1/3
Remaining part of the tank = 1 - 1/3 = 2/3
Time taken by A + B to fill this 2/3rd part of the tank = 8 h
A and B together can fill tank in 12 h (i.e., 8 x 3/2).
Now, we have A, B and C together filling the tank in 6 h and A and B together fill tank in 12 h.
Work done by C alone in 1 h = 1/6 - 1/12 = 1/12
Hence, C alone can fill the tank in 12 h.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.