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  • Question
  • 640 ml of a mixture contains milk and water in ratio 6:2. How much of the water is to be added to get a new mixture containing half milk and half water?


  • Options
  • A. 310 ml
  • B. 320 ml
  • C. 330 ml
  • D. 340 ml

  • Correct Answer
  • 320 ml 

    Explanation

    Let us assume the ratio product is Q.
    According to question,
    Quantity of Milk in mixture = 6Q ml
    Quantity of Water in mixture = 2Q ml
    Quantity of Milk in mixture + Quantity of Water in mixture = 640
    6Q + 2Q = 640
    8Q = 640
    Q = 640/8
    Q = 80
    Quantity of Milk in mixture = 6Q ml = 6 x 80 = 480 ml
    Quantity of Water in mixture = 2Q ml = 2 x 80 = 160 ml
    To find the new mixture containing half milk and half water,
    Quantity of water to be added for making the mixture of equal quantity of milk and water = 480 - 160 = 320


  • More questions

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    • A. ? 16537.50
    • B. ? 18000
    • C. ? 19000.50
    • D. ? 20000
    • Discuss
    • 2. 
      The value of k for which kx + 3y - k + 3 = 0 and 12x + ky = k, have infinite solutions, is

    • Options
    • A. 0
    • B. -6
    • C. 6
    • D. 1
    • Discuss
    • 3. 8, 24, 12, 36, 18, 54, (....)

    • Options
    • A. 27
    • B. 108
    • C. 68
    • D. 72
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    • 4. 
      solve 6x + 3y = 7xy and 3x + 9y = 11xy.

    • Options
    • A. x=1, y=3/2
    • B. x=-1, y = 3/2
    • C. x=3/2, y=1/2
    • D. x=1, y= -3/2
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    • 5. 
      The numerator of a fraction is 6x + 1 and the denominator is 7 - 4x, x can have any value between -2 and 2, both included. The values of x for which the numerator is greater

    • Options
    • A. 3/5 < x ? 2
    • B. 3/5 ? x ? 2
    • C. 0 < x ? 2
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    • 6. 
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    • Options
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    • 7. 
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    • Options
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    • Discuss
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    • Options
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    • Discuss
    • 9. 
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    • 10. 
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