Let us assume the ratio product is Q.
According to question,
Quantity of Milk in mixture = 6Q ml
Quantity of Water in mixture = 2Q ml
Quantity of Milk in mixture + Quantity of Water in mixture = 640
6Q + 2Q = 640
8Q = 640
Q = 640/8
Q = 80
Quantity of Milk in mixture = 6Q ml = 6 x 80 = 480 ml
Quantity of Water in mixture = 2Q ml = 2 x 80 = 160 ml
To find the new mixture containing half milk and half water,
Quantity of water to be added for making the mixture of equal quantity of milk and water = 480 - 160 = 320
Given P = ? 15000 , R = 10 %
and n = 1 yr
Accounting to the formula,
Amount = P(1 + R/(2 x 100))2n
= 15000 x (1 + 5/100 )2
= 15000 x (105/100 )2
= 15000 x (21/20) x (21/20)
= ? 16537.50
For infinite solution
a1/a2 = b1/2 = c1/c2
? K/12 = 3/K = (-K + 3)/ -K
? K/12 = 3/K
? K2 = 36
? K = ?36 = 6
So, the next number = 54 ? 2 = 27.
Given equation are 6x + 3y = 7xy
? (6/y) + (3/x) = 7 .....(i)
And 3x + 9y = 11xy
? (3/y) + (9/x) = 11 .....(ii)
On multiplying Eq. (ii) by 2 and subtracting from Eq. (i), we get
(6/y) + (3/x) = 7
(6/y) + (18/x) = 22
-------------------------
- 15/x = - 15
? x = 1
On putting this value in Eq. (i), we get
(6/y) + 3 = 7
? 6/y = 4
? y = 6/4 = 3/2
6x + 1 > 7 - 4x
? x > 3/5
? 3/5 < x ? 2
? 2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = k
? A = 5(k - 40)/2, B =7(k - 20)/2 and C = 17(k - 10)/9
? 5(k - 40)/2 +7(k - 20)/2 +17/(k - 10 )/9 = 600
? 45k - 1800 + 63k - 1260 + 34k - 340 = 10800
? 142k = 14200
? k = 14200 / 142 = 100
Hence A's share = (5/2) x ( 100 - 40) = Rs. 150
Let hens = H, goats = G
According to the question,
H + G = 90 ...(i)
2H + 4G = 248 ...(ii)
On multiplying Eq. (i) by 2 and subtracting from Eq. (ii) , we get
2H + 2G = 180
2H + 4G = 248
-------------------
-2G = -68
? G = 34
Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
∴ Ratio of first two numbers = | ❨ | 6x | : | 3x | ❩ | = 12x : 15x = 4 : 5. |
5 | 2 |
we have, x + y - 7 = 0
? x + y = 7 ...(i)
and 3x + y - 13 = 0
? 3x + y = 13 ..(ii)
By subtracting Eq. (i) from Eq. (ii), we get
3x + y = 13
x + y = 7
----------------------
2x = 6 ...(ii)
? x = 3
On putting the value of x in Eq. (i), we get
3 + y = 7
? y = 4
Now, 4x2 + y2 + 4xy
= 4 x (3)2 + (4)2 + 4 x 3 x 4
= 4 x 9 + 16 + 48
= 36 + 16 + 48 = 100
Let the number be P and Q
According to the question
(P + Q) = 2.5 (P - Q)
? P + Q = 2.5P - 25Q
? 3.5Q = 1.5P
? P / Q = 7/3 .....(i)
Now PQ = 84
? Q2 = (84 x 3) / 7
? Q2 = 36
? Q = 6
&ther4; P = (7/3) x 6 = 14
Sum of the number = P + Q = 14 + 6 = 20
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