Let the number of boys and girls be x and y respectively. Then
From question, (x - y ) = 12% of (x + y)
? x/y = 3/25 (x + y )
? 25x - 25y = 3x + 3y
? 22x = 28y
? x / y = 28 / 22 = 14 / 11
5 x 1.6 - 2 x 1.4 | =? |
1.3 |
Given Expression = | 8 - 2.8 | = | 5.2 | = | 52 | = 4. |
1.3 | 1.3 | 13 |
0.6 + . 7 + .8 + .3
= ( 6/9 + 7/9 + 8/9 + 3/9)
= 24 / 9
= 8 / 3
= 22/3
Let B will take N days to complete the remaining job.
According to the question
(1/A) + (1/B) = 1/24 and 1/A = 1/32
? 1/B = (1/24) - (1/32) = 1/96
? B = 96 days
According to the question,
8[(1/A) + (1/B)] + N x (1/B) = 1
? 8 x (1/24) + (N/96) = 1
? (1/3) + (N/96) = 1
? N/96 = 1 -1/3
? N = (2 x 96)/3 = 64
Hence, B complete the remaining job in 64 days
Let B left work after N days from the start.
According to the question,
N/25 + (N + 7)/15 = 1
? (3N + 5N + 35) / 75 = 1
? 8N = 75 - 35
? N = 40/8
? N = 5
Let the length of the train be L m.
According to the question,
L/9 = Speed ...(i)
and (L + 150)/15 = Speed ..(ii)
from Eqs. (i) and (ii) we get
L/9 = (L + 150)/15
? L/3 = (L + 150)/5
? 5L = 3L + 450
? L = 225 m
( | x + |
|
) | 2 | - |
|
( | x - |
|
) | = 4 is : |
x | 2 | x |
∴ Required number of ways |
= (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4) | |||||||||||||||||||
= (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2) | ||||||||||||||||||||
|
||||||||||||||||||||
= (24 + 90 + 80 + 15) | ||||||||||||||||||||
= 209. |
Net part filed in 1 h = (1/20 + 1/30 - 1/40) = 7/120
Hence, the tank will be full in 120/7 = 171/7 h
Number of regular hours during 4 weeks = 8 x 5 x 4 = 160
Amount paid for regular working hours = 160 x 5 = ? 800
Balance left = (920 - 800) = ? 120
So, ? 120 is paid for his over time at ? 8 per h.
? Total number of overtime working hours = 120/8 = 15 h
Total working hours = (160 + 15) = 175 h
Portion of work completed by one man in 11/2 days.
i.e., 3/2 days = 3/(2 x 3) = 1/2
Portion of work completed by one women in 11/2 days.
i.e., 3/2 days = 3/(2 x 4) = 3/8
? Portion of work completed by boys = 1 - (1/2 + 3/8) = 1/8
Now, portion of work completed by each boy in 3/2 days = 3/(2 x 12) = 1/8
Hence, only one boys would be required.
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