Ramesh's 1 day's work = 1/12
Suresh's 1 day's work = 1/16
(Ramesh + Suresh)'s 1 day work = (1/12) + (1/16)
= (16 + 12) / (12 x 16)
= 28/192
= 7/48
Given that, (Ramesh + Suresh + Boy)'s
1 day's work = 1/6
? Boy's 1 day's work = (1/6) - (7/48) = (8 - 7)/ 48 = 1/48
? Ramesh's share : Suresh's share : Boy's share = 1/12 : 1/16 : 1/48
= (8/96) : (6/96) : (2/96)
= 8 : 6 : 2
= 4 : 3 : 1
Let Ramesh's share be 4k , Suresh's share be 3k and boy's share be k.
According to the question,
4k + 3k + k = 800
8k = 800
? k = 800/8 = 100
? Ramesh's share = 4k = 4 x 100 = ? 400
Suresh's share = 3k = 3 x 100 = ? 300
Boy's share = k = ? 100
Four tenths = 0.4
Five thousandths = 0.005
The average is (0.4 + 0.005)/2 = 0.2025
We have to rearrange the equation to make R the subject.
Start by cross multiplying by (r + R); V (r + R) = 12R
Multiply out the bracket Vr + VR = 12R
LCM of (80, 85, 90) can be found by prime factorizing them.
80 ? 2 × 2 × 2 × 2 × 5
85 ? 17 × 5
90 ? 2 × 3 × 3 × 5
L.C.M of (80,85,90) = 2 × 2 x 2 × 2 × 3 × 3 × 5 × 17
= 16 x 9 x 85
= 144 x 85
= 12240
L.C.M of (80,85,90) = 12240.
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