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- Question
- A shopkeeper sells transistors at 15% above its cost price. If he had bought it at 5% more than what he paid for it and sold it for ? 6 more, he would have gained 10%. The cost price of the transistor is?
Options- A. ? 800
- B. ? 1000
- C. ? 1200
- D. ? 1400
- Correct Answer
- ? 1200
ExplanationLet cost price of transistor = ? N
According to the question,
CP of transistor = (N x 105)/100
And SP of transistor = (115 x N)/100 + 6
? Profit percentage = (SP - CP)/CP x 100
? 10 = [[(115N/100) + 6 - (105N/100)] / (105N/100)] x 100
? 10 = [(10N + 600) x 100]/ 105N
? 105N = 100N + 6000
? 5N = 6000
? N= ? 1200 - 1. Cost of a packet of coffee powder and a litre of milk are ? 20 and ? 30 respectively. 10 cups of coffee is made with one packet coffee powder and for each cup 200 ml of milk is used. If coffee is sold at 25% profit, the selling price of each cup of coffee is
Options- A. ? 12.50
- B. ? 6.25
- C. ? 8
- D. ? 10 Discuss
- 2. A dealer buys an article marked at ? 25000 with 20% and 5% off. He spends ? 2000 on its repair and sells it for ? 25000. What is his gain or loss per cent?
Options- A. 21% loss
- B. 10.50% loss
- C. 19.05% gain
- D. 25% gain Discuss
- 3. A merchant has 1000 kg of sugar, part of which he sells at 8% profit and the rest at 18% profit. He gains 14% on the whole. The quantity sold at 18% profit is
Options- A. 500 kg
- B. 600 kg
- C. 400 kg
- D. 640 kg Discuss
- 4. A trader purchases a watch and a wall clock for ? 390. He sells them making a profit of 10% on the watch and 15% on the wall clock. He earnes a profit of ? 51.50. The difference between the original prices of the wall clock and the watch is equal to
Options- A. ? 110
- B. ? 100
- C. ? 80
- D. ? 120 Discuss
- 5. An article passing through two hands is sold at a profit of 40% at the original cost price. If the 1st dealer makes a profit of 20%, then the profit per cent made by the second is
Options- A. 151/3%
- B. 151/3%
- C. 162/3%
- D. 132/3% Discuss
- 6. A merchant earns a profit of 20% by selling a basket containing 80 apples whose cost is ? 240 but he gives one-fourth of it to his friend at cost price and sells the remaining apples. In order to earn the same profit, at what price must he sell each apple?
Options- A. ? 3.00
- B. ? 3.60
- C. ? 3.80
- D. ? 4.80 Discuss
- 7. A bookseller sells a book at a gain of 10%. if he had bought it at 4% less and sold it for ? 6 more, he would have gained 118 3/ 4%. The CP of the book is?
Options- A. ? 130
- B. ? 140
- C. ? 150
- D. ? 160 Discuss
- 8. Assuming that profit of a shopkeeper in a particular commodity is a linear expression of transportation charge (t) and the quantity of commodity (q) . He earns a profit of ? 10000 by selling 20 units at the transport charge of ? 400. He also earn a profit of ? 12000 by selling 25 units at the transport charge of ? 600. What is the linear expression in t and q?
Options- A. 600q - 5t
- B. 500q - 4t
- C. 600q - 4t
- D. 500q - 5t Discuss
- 9. A person sold a table at a gain of 15%. Had he bought it for 25% less and sold it for ? 60 less, he would have made a profit of 32%. The cost price of table was
Options- A. ? 300
- B. ? 350
- C. ? 375
- D. ? 400 Discuss
- 10. A person bought two bicycles for ? 1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get ? 5 more. The difference in the cost price of the two bicycles was
Options- A. ? 25
- B. ? 75
- C. ? 50
- D. ? 40 Discuss
Profit and Loss problems
Search Results
Correct Answer: ? 10
Explanation:
Cost of coffee powder used in one cup = 20/10 = ? 2
Cost of milk used in one cup = (30/1000) x 200 = ? 6
? Cost of each cup coffee = 2 + 6 = ? 8
To gain 25% profit, sale price of each cup of coffee = 125% of 8 = ? 10
Correct Answer: 19.05% gain
Explanation:
Total CP = (95% of 80% of ? 25000) + (2000)
= (95/100) x (80/100) x 25000 + 2000
= 19000 + 2000 = ? 21000
? CP = ? 21000 and SP = ? 25000
? Gain = 25000 - 21000 = ? 4000
? Gain % = (4000/21000) x 100% = 400/21%
= 19.05% (approx.)
Correct Answer: 600 kg
Explanation:
Let the sugar sold at 8% gain = P
? Sugar sold at 18% gain = (1000 - P)
Let CP of sugar = ? Q per kg
Total CP = ? 1000 x Q
? [(108/100) x PQ)] + [(118/100) x (1000 - P) x Q]
= (114/100) x 1000 Q
? 108PQ + 118000Q - 118PQ = 114000Q
? 10P = 4000
? P = 400
? Quantity sold at 18% profit = 1000 - 400 = 600 kg
Correct Answer: ? 110
Explanation:
Let cost price of a wall clock = ? N
? Cost price of a watch = ? (390 - N)
According to the question,
{(N x 10)/100} + {(390 - N) x 15}/100 = 51.50
? 390 x 15 - 5N = 51.50 x 100
? 5N = 5850 - 5150 = 700
? N = 700/5 = 140
? Required difference = (390 - N) - N
= 390 - (2 x 140)
= 390 - 280 = 110
= ? 110
Correct Answer: 151/3%
Explanation:
Let CP = ? 100
Then, SP = ? 140
Let the profit made by the 2nd dealer = N%
Then, (100 + N)% of 120% of ? 100 = ? 140
? [(100 + N)/100 x (120/100) ] / 100 = 140
? 6(100 + N) = 700
? 600 + 6N = 700
? 6N = 100
? N = (100/6)% = (50/3) %
= 162/3
Correct Answer: ? 3.80
Explanation:
? CP of 80 apples = ? 240
? CP of 1 apples = ? 3
? CP of 20 apples = ? 60
To earn a profit of 20%
SP = 120% of 240 = ? 288
But he sales 1/4 of his apples i.e., 20 apples for ? 60
? SP of remaining 60 apples = 288 - 60 = ? 228
? SP of 1 apple = 228/60 = ? 3.80
Correct Answer: ? 150
Explanation:
Let CP = N
Then, SP = 110N / 100 = ? 11N/10
Now, CP = 96% of N = 96N/100 = ? 24N/25
Now, according to the question,
SP = ? (11N/10) + 6
? (11N/10) + 6 = 1183/4% of 24N/25
? (11N + 60)/10 = (475/400) x (24N/25) = 57N/50
? 550N + 3000 = 570N
? 20N = 3000
? N = 3000/20 = 150
? CP = ? 150
Correct Answer: 500q - 5t
Explanation:
By hit and trial ,
Case I t = ? 400 and q = 20 unit
Then, from option (a),
Total profit = 600q - 5t
= 600 x 20 - 5 x 400
= 12000 - 2000 = ? 10000
Case II t ? 600 and q = 25 units
Total profit = 600q - 5t
= 600 x 25 - 5 x 600
= 600(25 - 5)
= 600 x 20
= ? 12000
Correct Answer: ? 375
Explanation:
Let the cost price of table = ? N
Then, selling price with 15% gain
= (100 + Gain%) x CP/100
= (100 + 15)% x CP/100
= (115 x N)/100 = ? 115N/100
Now CP = [(100 - 25%) x CP]/100 = ? 75N/100
New SP = ? (115N/100) - 60
Now, according to the question,
[[(115/100 )- 60) - (75N/100)]/ (75N/100)] x 100 = 32
? [[(115N - 6000 - 75N)/100 ]/ (75N/100)] x 100 = 32
? [(40N - 6000)/75N] x 100 =32
? (40N - 6000)/(3N x 4) = 32
? 160N - 24000 = 96N
? 160N - 96N = 24000
? 64N = 24000
? N = 24000/64
? N = ? 375
? The cost price of table is ? 375.
Correct Answer: ? 50
Explanation:
Let the cost price of first bicycle be ? P.
Then, the cost price of second bicycle = ? (1600 - P)
According to the given condition,
[20% of P + 10% of (1600 - P )] - [10% of P + 20% of (1600 - P)] = 5
? [(20P/100) + [10 x (1600 - P)]/100] - [(10P/100) + {20 x (1600 - P)}/100] = 5
? (P/5 + (1600 - P)/10) - (P/10 + (1600 - P)/5) = 5
? P/5 - P/10 + (1600 - P)/10 - (1600 - P)/5 = 5
? 2P = 1600 + 50
? P = 1650/2 = 825
? Cost of second bicycle = (1600 - 825) = ? 775
? Required difference = 825 - 775 = ? 50
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