? Profit is maximum when C.P. is minimum and S.P. is maximum
Thus, C.P. = Rs. (200 x 8) = Rs. 1600
S.P. = Rs. (425 x 8) = Rs. 3400
? Gain = Rs. 1800
S.P. = 90% of Rs. 200 = Rs. 180
Required S.P. = (95% of Rs. 180) Rs. 171
Let the cost of each table and chair be Rs. x and Rs. y respectively
? 2y + 3x = 1025
and 3y + 2x = 1100
Solving the above two equations, we get
x = Rs. 175 and y = Rs. 250
? Difference between the cost of one table and one chair = Rs. (250 - 175) = Rs. 75
? C.P. of 1 article = (200/125) x 100 = Rs. 160
? C.P.of 6 articles = 6 x 160 = 960
? profit = 1056 - 960 = 96
percentage profit = (96/960) x 100 = 10%
Let C.P. of each article = Re. 1
Then, C.P. of 12 articles = Rs.12
S.P. of 12 articles = C.P. of 15 articles = Rs. 15
? Gain% = (3/12) x 100% = 25%
The profit = SP - CP
If SP and CP both increase at same amount then the profit would be same.
As we know profit % (Z) = Actual profit / CP
So if CP increases the profit % (Z) will go down as there is no change in actual profit.
? Gain = (S.P. of 8 dozen ) - (C.P. of 8 dozen )
? (S.P. of 1 dozen) = (S.P. of 8 dozen ) - (C.P. of 8 dozen)
? (C.P. of 8 dozen ) = (S.P. of 7 dozen)
Let C.P. of each dozen be Re. 1
? C.P. of 7 dozen = Rs. 7
? S.P. of 7 dozen = Rs. 8
? Gain % = (1 / 7 x 100)% = 142/7 %
? Loss = C.P. of 36 oranges - S.P. of 36 oranges
? S.P. of 4 = C.P. of 36 - S.P.of 36
? S.P.of 40 = C.P. of 36
Let C.P. of each oranges = Re. 1
? C.P.of 40 = Rs. 40
? S.P. of 40 = Rs. 36
? Loss = (4 / 40 ) x 100 % = 10%
Let the marked price be Rs. x
Then, (7% of x ) - 15 = 5% of x
? 7x / 100 - 5x / 100 = 15
? x = 750
Cost of the horse paid by A = (4860 x 100) / 81 = Rs. 6000
Cost of the horse paid by C = (6000 x 117) / 100 = Rs. 7020
Gain of B = Rs. 7020 - Rs. 4860 = Rs. 2160
Let the C.P. be Rs. x
Then, S.P. when gain is 12% = 12x / 100
? 112x / 100 - 88x / 100 = 6
? 24x / 100 = 6
? x = 600 / 24 = Rs. 25
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