A trader sells two articles, one at a loss of 10% and another at a profit of 15% but finally there is no loss or gain.If the total sale price of these two articles is Rs.30,000, find the difference between there cost price :

Abhishek Discount = 2800
Bhanu Discount =2400+640=3040

The difference in selling price is same as difference in discount = 3040 - 2800 = Rs.240

6.66% of MP = 25
? MP = 375
? SP = MP - 25 = 350

He sells 95 litre petrol at the price of 100 litre.
So profit % = [ 5 / 95 ] X 100 = 5.26%

Its simple i.e. 25% nothing else, which is very obvious

Loss % = ( common gain or loss / 10 )² %
= (20 / 10)² %
= 4%

Now assume total CP of both articles be x, then SP = 0.96x = 400
x = 400 / 0.96 = CP

loss = 4% of CP
= (4 / 100) X (400 / 0.96) = Rs. 16.66

Let the cost price of 1 litre pure milk be Rs. 1, then
for 6 litres (milk) CP = Rs. 6
for 2 litres (Water) CP = Rs. 0

and for 8 litres mixture SP = 8 x 2 = Rs.16

Profit = [(16-6) / 6] x 100 = 1000 / 6 = 166.66 %

Initially :
CP =100
SP = 140 (Since profit = 40 %)

New price :
CP =100
SP = 140 - 20% = 112
MP = 140

Profit % = [(112 - 100 )/100] = 12 %

CP : MP = 2y : 3y
profit = y
(%) profit : (%) discount =3 : 2

Let CP=200, SP=300
So [ (3y / 100) x 200 ] + [(2y/100) x 300] = 100
y= 8.33 %
Discount 2y = 16.66 %

Let the MP = Re. 1 per kg then
Initially :
Weight = 100 kg
MP = Rs. 100
Rate = 1 Rs / kg.

Finally :
Weight = 96 kg
MP = Rs. 96
Rate = 80 / SP = 80/96

Effective discount = 1- 80 / 96 = 16 / 96
% discount = [(16 / 96) ]x 100 = 16.66 %

K = 1 litre, price of K = 1
P = 4 litre price of P = 2

price of total (new) mixture = 1 X 1 + 4 X 2 = Rs. 9
price of pure petrol of same quantity = 5 X 2 = Rs. 10
Percentage profit = [(10-9) / 9] x 100 = 11¹/₉ %