Mr.Mittal purchased a car for Rs. 3,00,000 and a bike for his son for Rs. 1,00,000. He sold the car at a profit of 10% and bike at a loss of 20%. What is the net gain or loss?

You can go through options.
CP = 100 / 6 = 16.66 paisa
SP = 100 / 5 = 20 paisa

Profit (%) = [( 20 - 16.66 ) / 16.66 ] X 100
= [ 3.33 /16.66 ] X 100
= ( 1 / 5 ) X 100 = 20%
Hence, option (c) is correct.


Alternatively:
CP = 100 / 6
SP = ( 100 / 6 ) X 1.2 = 100 / 5

Hence, he should sell 5 toffees for Re. 1 (100 paisa)

Selling price after 10 % loss = 200 - 10% = 180
Selling price after additional 5% loss = 180 - 5% = 171

The cost price ( CP ) of profitable cow = 9900 / 1.1 = 9000
and profit = Rs. 900

The CP of loss yielding cow = 9900 / 0.8 =12375
and loss = Rs. 2475

So the net loss = 2475 - 900 = 1575

6% of cost price (CP) = 1425 - 1353 = 72
? CP = ( 72 x 100 ) / 6 = 1200

SP = 100/12 paise
Let's CP = x
SP = 0.8x = 100/12
? x = 10/(0.8x12) paise
Therefore, CP = 100/9.6 paise

Thus the new SP (with 20% profit) = 100/9.6 X 1.2 = 100/8 paise
Hence, 8 apples can be purchased for Rs.1 to gain 20%

Let the original price be 100 Rs.
So reduced price = 100 X 0.95 X 0.90 X 0.80 = 68.40

? Single discount = (100 ? 68.4) % = 31.6%

Let the price be y , then
y x 0.8 x 0.9 = 468
? x=650, therefore marked price = Rs. 650


Alternatively : 650 X 0.8 X 0.2 = 468
Hence option (d) is correct

CP of A + B + c = 2xy + 5x*2y - 2x*4y = 20xy

profit of A = 0.2xy
profit of B = 2xy
profit of C = 2xy
Total profit = 4.2xy

% profit = (4.2xy / 20xy) X 100 = 21%

Go through option C

180 x 12 x 1.2 + 180 x 8 x 1.1 = 180 [ 14.4 + 8.8 ]
= 180 (23.2) = 4176

And 180 x 20 x 1.15 = 4140

Therefore loss = 4176 - 4140 = 36
Hence option (c) is correct

CP / SP = 29x / 19x
loss % = 29x - 19x / 29x X 100 = 34.48 %

(To understand the concept assume CP of each article Rs 29 and SP of each article = Rs. 19)