Selling price after 10 % loss = 200 - 10% = 180
Selling price after additional 5% loss = 180 - 5% = 171
The cost price ( CP ) of profitable cow = 9900 / 1.1 = 9000
and profit = Rs. 900
The CP of loss yielding cow = 9900 / 0.8 =12375
and loss = Rs. 2475
So the net loss = 2475 - 900 = 1575
6% of cost price (CP) = 1425 - 1353 = 72
? CP = ( 72 x 100 ) / 6 = 1200
SP = 100/12 paise
Let's CP = x
SP = 0.8x = 100/12
? x = 10/(0.8x12) paise
Therefore, CP = 100/9.6 paise
Thus the new SP (with 20% profit) = 100/9.6 X 1.2 = 100/8 paise
Hence, 8 apples can be purchased for Rs.1 to gain 20%
Let the CP be Rs. x , then SP be 0.96x
? 0.96x = 240
? x = 250
Now the new SP = 250 X 1.1 = 275
From question CP/SP = 12/18 = 2/3
? Profit (%) = ( 3 - 2 ) / 2 x 100 = 50%
2nd Solution:
CP = 100/18 = 5.55 paisa
SP = 100/12 = 8.33 paisa
? Profit = (8.33-5.55)/5.55 x 100 = 50 %
You can go through options.
CP = 100 / 6 = 16.66 paisa
SP = 100 / 5 = 20 paisa
Profit (%) = [( 20 - 16.66 ) / 16.66 ] X 100
= [ 3.33 /16.66 ] X 100
= ( 1 / 5 ) X 100 = 20%
Hence, option (c) is correct.
Alternatively:
CP = 100 / 6
SP = ( 100 / 6 ) X 1.2 = 100 / 5
Hence, he should sell 5 toffees for Re. 1 (100 paisa)
Gain = 10% of 3,00,000 = 30000
Loss = 20% of 1,00,000 = 20000
Net gain = 10000 over Rs.4 lakh
Hence, profit = 10000/400000 x 100 = 2.5%
Let the original price be 100 Rs.
So reduced price = 100 X 0.95 X 0.90 X 0.80 = 68.40
? Single discount = (100 ? 68.4) % = 31.6%
Let the price be y , then
y x 0.8 x 0.9 = 468
? x=650, therefore marked price = Rs. 650
Alternatively : 650 X 0.8 X 0.2 = 468
Hence option (d) is correct
CP of A + B + c = 2xy + 5x*2y - 2x*4y = 20xy
profit of A = 0.2xy
profit of B = 2xy
profit of C = 2xy
Total profit = 4.2xy
% profit = (4.2xy / 20xy) X 100 = 21%
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