In a bangel shop, the shopkeeper displays the bangels in the form of a square, then he is left with 38 bangles with him. If he wants to increse the size of square by one unit each side of the square, he found that 25 bangles fall short of in completing the square. The actual number of bangles which he had with him in the shop was?

Total events = n (s) = 2⁵ = 32
n(E) of getting heads = 1
p(E) = 1/32
? n(E) = 1 - p(E) = 1 - 1/32 = 31/32

Number of trees that can be planted on one side of road = (1760 / 20) + 1
= 88 + 1
=89

? Trees on the both side = 2 x 89=178

1307 x 1307 = (1307)²
= (1300 + 7 )²
= (1300)² + (7)² + 2 x 1300 x 7
= 1690000 + 49 +18200
= 1708249

? 2?R - 2?r = (176-132)
? 2?(R-r) = 44
? R-r = ( 44 x 7 )/ (2 x 22)
= 7 m

Given Exp. = (1/2 x 1/4 + 20) / (2 + 20) = (161/8) x (1/22)
= 161 / 176

NA

If the required fraction be P
According to the question
(P x P) / (1/P) = 18²⁶/₂₇
? P³ = 512/27
? P = 8/3 = 2²/₃

(0.04)³ = 0.04 x 0.04 x 0.04
= 0.000064

We have p³ + q³ + r³ ? 3pqr = (p + q + r) (p² + q² + r² ?pq ? qr - rp)
Here p = a ? 4, q = b ? 3, r = c ?1
So, given expression is (p + q + r) (p² + q² + r² ? pq ? qr ? rp)
= (a ? 4 + b ? 3 + c ? 1) (p² + q² + r² ? pq ? qr ? rp)
= (a + b + c ? 8) (p² + q² + r² ? pq ? qr ? rp)
= (8 ? 8) (p² + q² + r² ? pq ? qr ? rp)
? (a ? 4)³ + (b ? 3)³ + (c ? 1)³ ? 3 (a ? 4) (b ? 3) (c ? 1) = 0

Let 3571 + x - 6086 = 115
Then, x = 6086 +115 -3571
= 6201-3571
= 2630