Concentration of Sulphuric acid = 80%
So in a 100cc, Sulphuric acid = 80cc and water = 20cc
Let x be the amount of water added to make concentration of 50%
?80/(100+x) = 50/100
? 80/(100+x) = 1/2
? x = 60cc
Let Cost Price (CP) = x
Then Selling Price(SP) if he sells at profit = x(1+8%) = 1.08x
and SP, if he sells at loss = x(1-8%) = 0.92%
Given, 1.08%-0.92% = Rs12
0.16x = Rs.12
?x = Rs.75
SP - CP = 480
1.2x - x = 480
?0.2x = 480
?x = 2400
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Total weight of alloy = 20+20+ 40 = 80g
Weight of tin = 20g
Percentage of tin = 20g/80g x 100
=25%
Final Price = 25 x (1 + 20/100) x (1 + 40/100)
=Rs.25 x 1.2 x 1.4
= Rs. 42
Final Price = Initial price + Initial price x 20/100
= Initial price x (1+20/100)
= Rs.300x(1.2)
= Rs.360
Let the number be y.
Then, 35% of y = 112
( 35 / 100 )y = 112
y = ( 112 x 100 ) / 35
= 320
Let 'x' be the required number
0.75x + 75 =x
? 0.25x=75
? x=75 / 0.25 =300
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