Let us assume
P = ?1 + a + ?1 - a
Square on both side,
P 2 = ( ?1 + a + ?1 - a ) 2
Use the formula ( a + b ) 2 = a 2 + b 2 + 2ab
we will get
? P 2 = (1 + a) + (1- a) + 2 ?1 + a x ?1 - a
? P 2 = (1 + a) + (1- a) + 2 ?(1 + a ) x ( 1 - a )
? P 2 = 2 + 2 ?1 - a2
? P 2 = 2 (1 + ?1 - a2)
Now put the value of a which is given in question;
? P 2 = 2 (1 + ?1 - ( ?3/2 )2)
? P 2 = 2(1 + ?1 - 3/4 )
? P 2 = 2(1 + ?1/4 )
? P 2 = 2(1 + 1/2) = 2 x 3/2 = 3
? P= ?3
? (?1 + a + ?1 - a) = ?3
In a game of 1000 meters, If A scores 1000 meters then B scores 950 meters and C scores 920 meters.
? B runs 1000 m while C scores 920 x 1000 / 950= 18400 / 19 m
Hence, in 1000 m race, B can give C (1000 - 18400 / 19) = 600 / 19 = 3111?19 meters start.
? loga3 = 1/3
? 3 = (a)1/3
? a = 27
Let the number be N,
Then, 137.5% of N = 33
? N = (33 x 100)/137.5 = 24
SP = 100/12 paise
Let's CP = x
SP = 0.8x = 100/12
? x = 10/(0.8x12) paise
Therefore, CP = 100/9.6 paise
Thus the new SP (with 20% profit) = 100/9.6 X 1.2 = 100/8 paise
Hence, 8 apples can be purchased for Rs.1 to gain 20%
CP = (100/30) x 400 = ? 4000/3
[? CP = {100/(100 - Loss%)} x SP]
Cost of the horse paid by A = (4860 x 100) / 81 = Rs. 6000
Cost of the horse paid by C = (6000 x 117) / 100 = Rs. 7020
Gain of B = Rs. 7020 - Rs. 4860 = Rs. 2160
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