Let MP = ? N
? SP = N x (100 - 10)/100 = ? 9N/10
? CP = (9N/10) x [100/(100 + 20)] = ? 3N/4
Thus, CP has to be increased by = [(N - 3N/4) / (3N/4)] x 100%
= [(N/4) / (3N/4)] x 100 %
= 331/3 %
Let the large number be x.
Then x - 20 = 20x/100
=> x - x/5 = 20 => x = 25.
Let the total amount he had with = Rs. p
From the given data,
p - 38460 - 24468 = 28p/100
p - 28p/100 = 24468 + 38460
72p/100 = 62928
72p = 62928 x 100
p = 62928 x 100/72
p = 87400
Hence, the total amount he had = p = Rs. 87400.
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(E U P) = 10/20 + 8/20 - 1/20 = 17/20
Let 'x' be the cost price.
Now Marked price = x + 30x/100 = 13x/10
10% discount = 10/100 x 13x/10 = 13x/100
Selling price = 13x/10 - 13x/100 = 117x/100
Given gain = 340
Here gain = 117x/100 - x = 17x/100 = 340 => x = Rs. 2000.
Lets say shyam sells at 100,
Since Ram sells 25% cheaper than Shyam,
Therefor Ram sells at less than 25% of100 or 75 rs.
Ram sells 25% dearer than Bram or 125% of Ram =100% of Bram or
125% of x (say x price of bram )=75rs.
or 100% of x =60rs.
hence price of bram is 60rs.
now Bram's good is cheaper than Shyam's as (100-60)x100/100% or 40%.
Hence Brams Good is 40% cheaper than that of Shyam's good.
Let the orginal salary = Rs. 100. New's salary = Rs.120.
Decrease on 120 = 20. Decrease on 100 = [(20/120)*100]% = (16 + 2/3) %.
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